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ser-zykov [4K]
3 years ago
11

Which of the following points lies on the circle whose center is at the origin and whose radius is 10?

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0
Circle at center at (h,k) and radis r is
(x-h)^2+(y-k)^2=r^2
r=10
(0,0) is center
(x-0)^2+(y+0)^2=10^2
x^2+y^2=100

test them

(-6,4)
x=-6 and y=4
36+16=42, not 100
not on it

sqrt 10 and sqrt10
10+10=20, not 100

(6,-8)
36+64=100
correct

answer is (6,-8)
SIZIF [17.4K]3 years ago
7 0

HE IS CORRECT!

THE ANSWER IS (6,-8)!!

BRUHHHHHHHHHHHHHHH!!!

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valina [46]
140 degrees, solve for the interior angle of LMK which can be found by 180-90-50 so now we know this is 40. However we need the other angle( KMU) that is supplemental with it, so 180-40 gives you 140 which is your final answer.


140 degrees
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balu736 [363]

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10.89 is the answers

Step-by-step explanation:

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3 years ago
Find the median mode range and any outliers. Then describe the data using them 77777,88,555,6,99,10101010,12
umka2103 [35]

Answer:

The median = 5

The mode  = 7

Range = 5

Outliers= None

Step-by-step explanation:

The median is the  value of the middle term.

The median is that value which divides the data into two equal halves.

7,7,7,7,7,8,8,5,5,5,6,9,9,10,10,10,10,12

There are 18 terms . So the middle term would be 9th term value= 5

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Range is the difference between the highest and lowest value.= 12- 7= 5

The interquartile range, IQR= q3 - q1 where q3= 10 and q1= 7

IQR= 10 −7=3

The inner fences can be found out by

q1−(1.5*IQR) and q3+(1.5*IQR)

=7−(1.5*3) and 10+(1.5*3)

Inner fences: 2.5 and 14.5

The outer fences are q1−(3*IQR) and q3+(3*IQR)

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Outer fences: -2 and 19

So if there are any outliers in this data set, they will either be less than -2 or greater than 19. But there are no outliers.

6 0
3 years ago
7. If U= {2, 4, 6, 8, 10, 12, 14, 16} and<br> A = {6, 10, 14}, what is A'?
Tresset [83]

The compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

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U = {2, 4, 6, 8, 10, 12, 14, 16}

We are also given that set A is:

A = {6, 10, 14}

We need to find A'

For this, we will subtract set A from the universal set, U.

So, we get that:

A' = U - A

A' = {2, 4, 6, 8, 10, 12, 14, 16} - {6, 10, 14}

Solving the expression, we get that:

A' = {2, 4, 8, 12, 16}

Therefore, we get that, the compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

Learn more about sets here:

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