Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
<em> </em><em>1</em><em>:</em><em>4</em>
<em>hope</em><em> </em><em>helpful</em><em> </em>:) !!!!
Answer:
B.Obtuse
as shown in the pictures that you put the angel is obtuse
Answer:
x = 1.24
Step-by-step explanation:
In order to get that x down from its current position of exponential, you need to take either the log or the natural log of both sides. The power rule tells us that we can then pull the exponent down in front. So let's take the natural log of both sides:
We can bring the x down in front to give us:
ln(83) = x ln(35)
The right side of this is "stuck" together by multiplication, so we can undo that multilication by division of the ln(35). That leaves us with just x on the right:
Do this on your calculator and find that x = 1.24
Answer:
<h3>
Acute Angles: ∠TLS, ∠SLT, ∠ULR</h3><h3>
Right Angles: ---------</h3><h3>
Obtuse Angles: ∠RLT, ∠SLU, ∠ULS,</h3><h3>
Straight Angles: ∠RLS, ∠TLU </h3><h3>
Not angles: ∠TRL </h3>
Step-by-step explanation:
The lines intersect at point L, so all angles have a vertex (middle letter) L so there is no angle TRL
Straight angle is a line with dot-vertex, so the straight angles are ∠RLS and ∠TLU.
∠TLS is less than 90° then it is acute angle (∠SLT is the same angle). ∠ULR is vertex angle to ∠TLS, so it's also acute angle.
Two angles adding to straight angle mean that they are both right angles or one is acute and the second is obtuse. ∠TLS is acute so ∠RLT is obtuse (they adding to ∠RLS) and ∠SLU is obtuse (they adding to ∠TLU). ∠ULS is the same angle as ∠SLU.
