Answer:
E = 30.37 J
Step-by-step explanation:
Given that,
The spring constant of the spring, k = 300 N/m
The spring is stretched by 0.45 m, x = 0.45 m
We need to find the elastic energy stored in the spring. The formula for the elastic energy is given by :
So, the required elastic energy is equal to 30.37 J.
(-infinity, -2)
(i’m not 100% positive, but i think its right)
Answer:
your answer is 91 over 5
Step-by-step explanation:
Answer:
Sol1 you can use "first(first+last)/2" is 138(138+1)/2 - 38(38+1)/2 = 8850
Sol2 or you can look this 39+40+41+....+100+(100+1)+(100+2)+....+(100+38) = 1+2+3+.....+99+100+100(38) = 5050+3800 =8850
