Find the values of the variables.
1 answer:
Answer:
x = 82
y = 98
z = 87
Step-by-step explanation:
By inscribed angle theorem:
x° and y° are the measures of the opposite angles of a cyclic quadrilateral.
Opposite angles of a parallelogram are supplementary.
Therefore,
x° + y° = 180°
82° + y° = 180°
y° = 180° - 82°
y° = 98°
y = 98
Similarly,
93° + z° = 180°
z° = 180° - 93°
z° = 87°
z = 87
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Answer:
option 4) x = 14 y = 7
Step-by-step explanation:
We are given a side angle and a side length so we can use trigonometry to find the solution
To find x we can use sine because the given side length is opposite to the angle so,
sin(60) =
solve for x and you get 14 (make sure you check that your calculator is in degrees)
for either use Pythagorean theorem or remove sine by tangent.
Answers
b = 2.77 m
A = 43.0°
C = 111.1°
cosine law to find b
b = 2.7708\ m
Find angle A with sine law
![\displaystyle \frac{\sin A}{a} = \frac{\sin B}{b} \\ \\ \sin A = \frac{a \sin B}{b} \\ \\ A = \sin^{-1} \left[ \frac{a \sin B}{b} \right] \\ \\ A = \sin^{-1} \left[ \frac{4.33 \sin 25.9}{2.7708} \right] \\ \\ A = 43.0467020](https://tex.z-dn.net/?f=%5Cdisplaystyle%0A%5Cfrac%7B%5Csin%20A%7D%7Ba%7D%20%3D%20%5Cfrac%7B%5Csin%20B%7D%7Bb%7D%20%5C%5C%20%5C%5C%0A%5Csin%20A%20%3D%20%5Cfrac%7Ba%20%5Csin%20B%7D%7Bb%7D%20%5C%5C%20%5C%5C%0AA%20%3D%20%5Csin%5E%7B-1%7D%20%5Cleft%5B%20%5Cfrac%7Ba%20%5Csin%20B%7D%7Bb%7D%20%20%5Cright%5D%20%5C%5C%20%5C%5C%0AA%20%3D%20%5Csin%5E%7B-1%7D%20%5Cleft%5B%20%5Cfrac%7B4.33%20%5Csin%2025.9%7D%7B2.7708%7D%20%20%5Cright%5D%20%20%5C%5C%20%5C%5C%0AA%20%3D%2043.0467020)
Find C with angles in triangle sum to 180
A + B + C = 180
C = 180 - A - B
C = 180 - 43.0467020 - 25.9
C = 111.1
b = 2.77 m
A = 43.0°
C = 111.1°
cosine law to find b
b = 2.7708\ m
Find angle A with sine law
Find C with angles in triangle sum to 180
A + B + C = 180
C = 180 - A - B
C = 180 - 43.0467020 - 25.9
C = 111.1
To show that the ratio is not constant for the function
we only need to evaluate this function at 2 points and then show that the ratio is not the same for those two points. Note that here
represents
.
To find the counter examples here, I will use the values and
. For
, the equation tells us that the output is
. For this value of
the point is point is
. The ratio
. For the
,
. For this value of
the point is
. The ratio
. Clearly this ratio is not constant for all ordered pairs.