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emmainna [20.7K]
3 years ago
12

Helpppp meeeee pleaseeee!!

Mathematics
2 answers:
Kitty [74]3 years ago
7 0
The answer is B because 5.93 is basicalyy 5.930 and 5.930 is bigger then 5.917

Eddi Din [679]3 years ago
6 0
Thr answer is B, because if you take the 7 off of 5.917 then it’s 5.91, so that means 5.93 is bigger than 5.91
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Write the equation for the line that passes through (-6, 1) and is perpendicular to
Dahasolnce [82]

Answer

(3,-2)

Explanation step by step

<em>y</em><em>=</em><em> </em><em> </em><em>-</em><em>2</em><em>x</em><em>-</em><em>9</em>

<em> </em><em> </em><em> </em><em>=</em><em> </em><em>-</em><em>2</em><em>(</em><em>-</em><em>6</em><em>,</em><em>1</em><em>)</em><em>-</em><em>9</em>

<em>=</em><em> </em><em>(</em><em>1</em><em>2</em><em>,</em><em>-</em><em>2</em><em>)</em><em>-</em><em>9</em>

<em>=</em><em>(</em><em>3</em><em>,</em><em>-</em><em>2</em><em>)</em>

8 0
3 years ago
How to solve this question
erica [24]
Multiplication property; distribution property of an exponent. Multiply exponents together, then distribute the ¨( )¨
3 0
3 years ago
Can someone help me pretty please?!?
Ostrovityanka [42]
A.) 7y+14. Because 7 is the amount he will increase each year (y) so 7y represents each year added, plus 14 (the amount he already can do per minute)
3 0
4 years ago
The gravitational force exerted on a baseball is 2.24 N down. A pitcher throws the ball horizontally with velocity 17.0 m/s by u
Fittoniya [83]
To have a weight of 2.21N., the ball's mass is (2.21/9.8) = .226kg. 
<span>a) d = 1/2 (vt), = 1/2 (18 x .17), = 1.53m. </span>
<span>b) Acceleration of the ball = (v/t), = 18/.17, = 105.88m/sec^2. </span>
<span>f = (ma), = .226 x 105.88, = 23.92N. </span>
4 0
4 years ago
Fine the exact distance between the line 6x-y=-3 and the point (6,2). Show your work. Explain your answer.
AVprozaik [17]

Answer:

\sqrt{37} units

Step-by-step explanation:

If we draw a perpendicular from point (6,2) on the line 6x - y = - 3, then we have to find the length of the perpendicular.  

We know the formula of length of perpendicular from a point (x_{1}, y_{1} ) to the straight line ax + by + c = 0 is given by  

\frac{|ax_{1} + by_{1} +c |}{\sqrt{a^{2}+b^{2}}}

Therefore, in our case the perpendicular distance is  

\frac{|6(6)-2+3|}{\sqrt{6^{2} +(-1)^{2} } } = \frac{37}{\sqrt{37} } = \sqrt{37}  units. (Answer)

6 0
4 years ago
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