1/x - 2/(x-3) = 4
multiply each side by x*(x-3)
x*(x-3)(1/x - 2/(x-3)) = 4*x*(x-3)
distribute
x*(x-3)(1/x) - 2/(x-3))x*(x-3) = 4*x*(x-3)
cancel
(x-3) - 2*x = 4x(x-3)
distribute
x-3-2x = 4x^2-12x
combine like terms
-x-3 = 4x^2 -12x
add x+3 to each side
0 = 4x^2 -12x+x+3
0 = 4x^2 -11x+3
using the quadratic formula
x= 11/8 - sqrt (73)/8
x=11/8 + sqrt (73)/8
The mean cost of transportation is £20.80
The peace of data that distorts the mean average is the taxi fares.
Step-by-step explanation:
Since the mean is the average, you add all the piece of date together then divide by the amount of data.
The equation for that would look something like this:
Answer:
The answer of your question is:
Step-by-step explanation:
Solve p² + 4p = 1
p² + 4p + (2)² = 1 + (2)²
(p + 2)² = 1 + 4
(p + 2)² = 5
(p + 2) = ±√5
p1 + 2 = √5 p2 + 2 = -√5
p1 = √5 - 2 p2 = -√5 + 2
p1 = 0.23 p2 = -0.23
Answer:
The answer is "failed to reject the null hypothesis" (it is not in the options available).
Step-by-step explanation:
If the P-value is bigger than the significance level, then the effect is statistically not significant. There is no enough evidence to reject the null hypothesis.
The answer is "failed to reject the null hypothesis" (it is not in the options available).
We know that sin(pi/6) = 1/2 and cos(pi/3) = 1/2. So arcsin and arccos is defined for x=1/2.
Now csc x = 1/sin x and sec x = 1/cos x.
So if csc x = 1/2, then sin x = 2, which is not in its domain. Same argument applies for sec x. You could think of this in terms of the graph too.
For arctan(x) and arccot(x), think of the graph. It is continuous everywhere and defined. Now one strategy you could use if you do not know of its graph is taking the graph of tan(x) and cot(x), restrict its domain and reflect it to obtain arctan(x) and arccot(x).