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JulsSmile [24]
4 years ago
11

juanita runs every third day and swims every fifth day. if juanita runs and swims today, in how many days will she run and swim

again on the same day
Mathematics
2 answers:
Korolek [52]4 years ago
6 0
On the 15th day she'll run and swim on the same day
anyanavicka [17]4 years ago
4 0
In 15 days she will run and swim on the same day again. 
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Write a paragraph proof.
taurus [48]

Step-by-step explanation:

Mid Point :  A point which lies on the line segment and is equidistant from both the ends of the segment is called a mid point.

A line segment can have ONLY ONE mid point and it divides the line segment into two equal parts.

Now, Given : C is the midpoint of AB.

                      and  B is the midpoint of CD.

⇒ AC = BC    and     BC = BD

Now by Euclid's Lemma

- "Things which are equal to the same thing are equal to each other."

Here, AC = BC , and BC = BD

⇒ AC = BD

Hence the result.

3 0
3 years ago
Read 2 more answers
Part III- Percentage Problems
blsea [12.9K]

The percentage of your savings that I use is 60%

This shows that the amount of money the organization will raise in total is $25,000.

1) Given

Total amount saved = $4500

Amount used = $2,700

Percentage of money used = Amount used/Total amount saved × 100%

Percentage of money used = 2700/4500 × 100%

Percentage of money = 27/45 ×100

Percentage of money used = 2700/45

Percentage of money used = 60%

Hence the percentage of your savings that I use is 60%

2) Let the amount of money the organization will raise in total be x

Since the 45% of the money they raise represents $11,250, hence:

45% of x = $11,250

0.45x = 11,250

x = 11,250/0.45

x = 25,000

This shows that the amount of money the organization will raise in total is $25,000

Learn more at brainly.com/question/18811795

3 0
3 years ago
A pole that is 3.5m tall casts a shadow that is 1.47m long. At the same time, a nearby tower casts a shadow that is 42.75m long.
Sonja [21]

Answer:

Therefore the height of the tower is 101.79 m.

Step-by-step explanation:

The ratio of the height of an object to the shadow of the object is always constant at certain time.

\frac{\textrm{The height of object}}{\textrm{The  shadow of the object}}= constant

\Rightarrow \frac{h_1}{s_1}=\frac{h_2}{s_2}

Given that,the length of the pole is 3.5 m and it casts a shadow that is 1.47 m long.

The length of shadow that castes by a tower is 42.75 m long.

Here h₁= 3.5 m, s₁=1.47 m, h₂= ? and s₂=42.75 m

\therefore \frac {3.5}{1.47}=\frac{h_2}{42.75}

⇒3.5 ×42.75 = h₂× 1.47

\Rightarrow h_2=\frac{3.5 \times 42.75}{1.47}

⇒h₂ = 101.79 m (approx)

Therefore the height of the tower is 101.79 m.

6 0
3 years ago
Photo used to help with the question is below!! Please answer! Will mark BRAINLIEST!
Degger [83]

Answer:

Area of Parallelogram = 120 in square

Area of Trapezoid =21.25cm square

Step-by-step explanation:

For Parallelogram A=15in x 8in

= 120in square

For Trapezoid

A=1/2*5(6+2.5)

=2.5(8.5)

=21.25cm square

4 0
3 years ago
Will give brainiest answer!!
Contact [7]
1)True
2)True
3)False
4)False
8 0
3 years ago
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