According to Vieta's Formulas, if
are solutions of a given quadratic equation:
Then:
is the completely factored form of
.
If choose
, then:
So, according to Vieta's formula, we can get:
But
:
![d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2](https://tex.z-dn.net/?f=d%5E4-8d%5E2%2B16%3D%28d%5E2-4%29%5E2%3D%5B%28d%2B2%29%28d-2%29%5D%5E2%3D%28d%2B2%29%5E2%28d-2%29%5E2)
3^2 goes onto the left side of the triangle
5^2 goes onto the bottom
x^ goes on the slant part of the triangle
X+y=2 (label equation one)
x-y=4 (label equation two)
y=-x+2 (equation one rearranged, label this equation equation three)
sub 3 into 2
x-(-x+2)=4
x+x-2=4
2x-2=4
2x=6
x=3
sub x=3 into equation one
3+y=2
y=-1
therefore x=3 and y=-1
Parallel to the y axis...that would mean that it is a vertical line.
The equation would be : x = 4 and it would have an undefined slope
Or 2 times 2 times 2 times 2 times 2 times 2 times 2
So, 2^6 is:
64
Now, 7^4 is:
2,401
Hope it helps!
