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Illusion [34]
3 years ago
13

12) Write the equation of the quadratic whose vertex is (-2,3) and a = -3.

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0
4/1&373; I need points ;)
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svp [43]
A 80 square meter I’m not quite sure
7 0
3 years ago
Help plssss!!! Giving. 10 pointsssssss
gayaneshka [121]

Answer:

its 34

Step-by-step explanation:

8 0
3 years ago
Needs help with linear equations got 10 questions in all the picture posted is the first one.
madreJ [45]
Your equation would be T=.002n.
5 0
3 years ago
I need help ASAP help me answer questions and then I put a picture up
olya-2409 [2.1K]

Answer:

(-4,9)

Step-by-step explanation:

To solve the system of equations, you want to be able to cancel out one of the variables. In this case, it'd be easiest to cancel out the x variables. To do this, you'll want to multiply everything in the first equation by 2 (2(x-5y=-49)=2x-10y=-98). Then, you can add the two equations together. 2x and -2x will cancel out, so you'll be left with -11y=-99. Next, solve for x by dividing both sides of the equation by -11, which will give you y=9. This is your y-coordinate! At this point, you're halfway to the answer as you just need your x-coordinate. It's not too difficult to find the x-coordinate, since you just substitute 9 into one of the equations. It doesn't matter which one you choose as you should get the same answer with both. I usually substitute the y-value into both equations, though, just to make sure I'm correct. Once you put the y-value into the equations, you should get x=-4 after solving it. :)

5 0
3 years ago
Find the value of the expression x3−y3+x2+y2+3 by substituting x=−2 and y=1.
vaieri [72.5K]

\\ \sf\dashrightarrow x^3-y^3+x^2+y^2+3

\\ \sf\dashrightarrow (-2)^3-(1)^3+(-2)^2+(1)^2+3

\\ \sf\dashrightarrow -8-1+4+1+3

\\ \sf\dashrightarrow -9+8

\\ \sf\dashrightarrow -1

8 0
3 years ago
Read 2 more answers
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