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boyakko [2]
4 years ago
8

Is it A)50 degrees, B) 60 degrees C) 74 degrees or D) 78 degrees

Mathematics
2 answers:
Slav-nsk [51]4 years ago
6 0

Answer:

a

Step-by-step explanation:

Viktor [21]4 years ago
5 0
The answer is 50 degrees witch is A
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A women has twice as many dimes as quarters in her purse.If the dimes were quarters and the quarters were dimes,she would have $
skad [1K]
2.98 i think dont come for if it not ok

3 0
4 years ago
Determine if each statement about the relation {(3,7),(5,1),(6,4),(2,5)} is true or false.
s2008m [1.1K]

Answer:

a. true

b. true

c. True

Step-by-step explanation:

a. The domain of a relation includes all possible set of data that are the x-values. Therefore, the domain of the relationship given would be: {2, 3, 5, 6}.

a is True.

b. The range includes all corresponding y-values. Therefore,

Range would be {1 4, 5, 7}

b is Tire.

c. There's 5 on both range and domain.

c is hungry.

8 0
3 years ago
What’s the reason for the fourth statement in this proof
Ksivusya [100]
What statement.........
8 0
3 years ago
30 ft
Alex

Answer:

32 ft

Step-by-step explanation:

find the area of the large rectangle:

30 x 16 = 480

find the area of the small rectangle:

10 x 8 = 80

subract the small rectangle from the big rectangle to get the area of the shaded region:

480 - 80 = 400

now plug this area and the height into the equation for triangle area:

A = bh/2

400 = b(25)/2 multiply both sides by 2

2(400) = 2(25b/2)

800 = 25b divide both sides by 25

800/25 = 25b/25

32 = b

6 0
3 years ago
Read 2 more answers
A random sample of 401 student were recent survey regarding their class standing freshmen software junior senior and their major
SOVA2 [1]

the Solution

Pr(\text{STEM)}=\frac{158}{401}=0.394Pr(\text{Sophomore)}=\frac{87}{401}=0.217Pr(sophomore|Non-stem)=\frac{68}{401}=0.170Pr(\text{sophomore and Non-stem)=}\frac{87}{401}\times\frac{243}{401}=\frac{21141}{160801}=0.1315

To ascertain whether Sophomore and Non-stem are dependent, we have to test the following:

\begin{gathered} If\text{ Pr(sophomore or Non-stem) = Pr(sophomore and Non-stem),} \\ \text{then we conclude that both events are Independent,} \\ \text{otherwise, they are dependent.} \end{gathered}\begin{gathered} Pr(\text{sophomore or Non-stem)=Pr(sophomore)+Pr(Non-stem)} \\ -Pr(\text{sophomore and Non-stem)} \end{gathered}Pr(\text{Sophomore or Non-stem)=}\frac{87}{401}+\frac{243}{401}-(\frac{87}{401}\times\frac{234}{401})=\frac{330}{401}-\frac{21141}{160801}=0.82294-0.13147=0.69147

Cleary, we have that sophomore and non-stem events are dependent events since 0.69147 is not the same as 0.13147.

4 0
1 year ago
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