Hello there!
<span>Find the volume of the cone. Use 3.14 as an approximation for pi. Round the answer to two decimal places.
A cone with radius of circular base of 6 centimeters and a height of 7 centimeters.
</span><span>C. 263.76cm3
</span>
Answer:
87.4%
Step-by-step explanation:
The radius to the top of the atmosphere as a fraction of the moon's radius is ...
(2575 +600)/2575 ≈ 1.23301
The ratio of the moon's volume with atmosphere to the moon's volume without is the cube of this, or 1.87456
Then the ratio of the atmosphere's volume to the moon's volume is ...
(1.87456 -1)/1 = 0.87456
Atmospheric haze is about 87.4% of the moon's volume.
_____
We have assumed that the desired ratio is to the solid moon's volume, not the volume of moon and atmosphere together. The latter ratio would be 0.875 to 1.875 or about 46.7%.
M(x)=−(x−5) 2 +25m, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 5, right parenthesis, squ
Aleksandr [31]
Answer:
25
Step-by-step explanation:
Given the function that represents the amount of mosquitoes as;
M(x) = -(x-5)² + 25
To get the maximum mosquitoes possible, we need to first find x;
At the maximum dM/dx = 0
dM//dx = -2(x-5)
0 = -2(x-5)
-2(x-5) = 0
-2x + 10 = 0
-2x = -10
x = 10/2
x = 5
Substitute x = 5 into the function;
M(5) = −(5−5)² +25
M(5) = 0+25
M(5) = 25
Hence the maximum number of mosquitoes is 25
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Below are the choices:
A) (2, 6)
<span>B) (4, 6) </span>
<span>C) (2, 5) </span>
<span>D) (4, 5)
</span>
The answer should be: (4, 5)
<span>E = (8, 8) -----> E' = (4, 4) = (8/2, 8/2)
</span><span>F = (8, 10) -----> F' = (8/2, 10/2) = (4, 5)</span>
Is there like a question???
