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Julli [10]
3 years ago
13

Find the value of the expression 2x cubed + 3y squared - 17 when x = 3 and y = 4.

Mathematics
2 answers:
Svetlanka [38]3 years ago
4 0
2x^3+3y^2-17\\\\subtitute\ the\ values\ of\ the\ x=3\ and\ y=4\ to\ the\ expression:\\\\2(3^3)+3(4^2)-17=2(27)+3(16)-17=54+48-17\\\\=102-17=\boxed{85}\\----------------------\\3^3=3\times3\times3=27\\\\4^2=4\times4=16
german3 years ago
3 0

Answer:85

Step-by-step explanation:

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There are 7 acts in a talent show.
lara31 [8.8K]

Answer:

<u><em></em></u>

  • <u><em>Event A: 1/35</em></u>
  • <u><em>Event B: 1/840</em></u>

<u><em></em></u>

Explanation:

<u>Event A</u>

For the event A, the order of the first 4 acts does not matter.

The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.

Thus, the number of ways that the first <em>four acts</em> can be scheduled is:

          C(m,n)=\dfrac{m!}{n!(m-n)!}

         C(7,4)=\dfrac{7!}{4!(7-4)!}=\dfrac{7!}{4!(3)!}=35

And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).

Therefore the<em> probability of Event A</em> is:

           P(A)=1/35

Event B

Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.

The number of ways in which <em>four acts </em>can be scheculed when the order matters is:

           P(m,n)=\dfrac{m!}{(m-n)!}

         P(m,n)=\dfrac{7!}{(7-4)!}=P(m,n)=\dfrac{7!}{4!}=840

The number of ways <em>the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth</em> is 1: P(4,4)

Therefore, <em>the probability of Event B</em> is:

            P(B)=1/840

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Step-by-step explanation:

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