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Gnesinka [82]
3 years ago
11

Write as an algebraic expression 17 decreased by x​

Mathematics
1 answer:
Lerok [7]3 years ago
8 0
The correct answer is 17-x
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Jessica saved a total of $58.50 to spend on school supplies. She wants to buy one backpack for $36.25 and she wants to spend the
Eduardwww [97]

Answer:

B. $36.25+$3.89x≤$58.50

Step-by-step explanation:

It has to be less than or equal to $58.50

4 0
4 years ago
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Which statement best describes the function below?
marta [7]
<h2>Answer:</h2>

A. It is a many-to-one function.

<h2>Step-by-step explanation:</h2>

Hello! It will be a pleasure to help to figure out what's the correct answer to this problem. First of all, we have the following function:

f(x) = 2x^3 + 2x^2-x

When plotting this function, we get the red graph of the function shown below. So let's solve this as follows:

<h3>A. It is a many-to-one function.</h3>

True

A function is said to be many-to-one there are values of the dependent variable (y-values) that corresponds to more than one value of the independent variable (x-values). To test this, we need to use the Horizontal Line Test. So let's take the horizontal line y=0.5, and you can see from the first figure below that y=0.5 is mapped onto x=-1.241 \ x=-0.344 \ and \ x=0.585. so this is a many-to-one function.

<h3>B. It is a one-to-one function.</h3><h3>False</h3>

Since this is a many-to-one function, it can't be a one-to-one function.

<h3>C. It is not a function.</h3>

False

Indeed, this is a function

<h3>D. It fails the vertical line test.​</h3>

False

It passes the vertical line test because any vertical line can intersect the graph of the function at most once. An example of this is shown in the second figure below.

6 0
4 years ago
I need help!! It’s proving trapezoids theorems
sweet [91]

Because ABCD is an isosceles trapezoid, the angles A and D are congruent.

BA and CD are congruent (given) and AD is congruent to itself (reflexive property).

Then triangles BAD and CDA form a pair of SAS triangles, so they are congruent.

BD and CA are corresponding parts in those triangles, so they are congruent (CPCTC).

7 0
3 years ago
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Rewrite the expression with a rational exponent as a radical expression.
Nuetrik [128]

Answer:

Rewriting the expression (3^\frac{2}{3})^\frac{1}{6} with a rational exponent as a radical expression we get \mathbf{\sqrt[9]{3} }

Step-by-step explanation:

We need to rewrite the expression (3^\frac{2}{3})^\frac{1}{6} with a rational exponent as a radical expression.

The expression given is:

(3^\frac{2}{3})^\frac{1}{6}

First we will simply the expression using exponent rule (a^m)^n=a^{mn}

(3^\frac{2}{3})^\frac{1}{6}\\=(3^\frac{2}{18})

As we know 2 and 18 are both divisible by 2, we can write

=(3^\frac{1}{9})

Now we know that a^\frac{1}{9}=\sqrt[9]{a}

Using this we get

=\sqrt[9]{3}

So, rewriting the expression (3^\frac{2}{3})^\frac{1}{6} with a rational exponent as a radical expression we get \mathbf{\sqrt[9]{3} }

3 0
3 years ago
*<br>87-1 = 25+2 simplifies to :​
Xelga [282]
It simply to nothing
3 0
3 years ago
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