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kkurt [141]
3 years ago
6

Find the value of x for which abcd must be a parallelogram

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
6 0
X+3=2x-1
3=x-1
4=x
x=4
PLZ Make Me Brainliest
LekaFEV [45]3 years ago
4 0

Answer:

x = 4 is the value for which ABCD will be a parallelogram.

Step-by-step explanation:

In the given figure ABCD is the parallelogram in which opposite sides AB is parallel and equal to CD.

Since BD is transverse so m∠ABD = m∠BDC

Therefore, (x + 3) = (2x - 1)

x = 2x - 1 - 3

x = 2x - 4

x - 2x = -4

-x = -4

x = 4

For x = 4, quadrilateral ABCD will be a parallelogram.

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gtnhenbr [62]

Answer:

The fourth line will have 15 marbles

Step-by-step explanation:

The third line has 7 marbles. So, you double that and add one in order to find the number of marbles in the fourth line.

7*2=14

14+1=15

4 0
3 years ago
What is the m?<br> -8 + 4m = 2
IgorLugansk [536]
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3 years ago
0.4(x-0.45)=9.2 PLZZZZZ HELP!!!!!!!
Helen [10]

Answer:

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5 0
2 years ago
. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an
Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12

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Z = \frac{X - \mu}{\sigma}

Z = \frac{59.5 - 56}{1.12}

Z = 3.1

Z = 3.1 has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

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3 years ago
Write the value represented on the number line next to the letter
miss Akunina [59]
Okay, I understand. You found the correct answer. I won't get points. Sniffle.Sniffle.
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