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4 years ago

Y=x^2+14x+49 focus point

Mathematics

1 answer:

aleksley [76]4 years ago

6 0

Answer:

(-7, 1/4)

Step-by-step explanation:

I have attached the work to your problem.

Please see the attachment below.

I hope this helps!

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Kimberly's family has a dinner bill of $26 and wants to leave a 15% tip for their server. How much tip are they leaving?

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3 years ago

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How many inches are in 4 meters?

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157.48 inches

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Answer:

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Step-by-step explanation:

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3 years ago

Bruce is going to call one person from his contacts at random. He has 25 total contacts. 20 of those contacts are from his neigh

Naya [18.7K]

<h3>P(call a person not from his neighborhood) = $(\frac{1}{5} )$ </h3>

Step-by-step explanation:

Here, the total number of contacts in the list if Bruce = 25 contacts

The total number of neighbors in the contact = 20 people

Now, let E: Event of calling a person from his neighborhood

So, P(E) = $\frac{\textrm{Total Favorable Outcomes}}{\textrm{Total Outcomes}} = \frac{20}{25} = (\frac{4}{5})$

So, the probability of calling a person from his neighborhood is $(\frac{4}{5} )$

⇒P(E) = $(\frac{4}{5} )$

Now,as we know: P(E) + P(not E) = 1

So, the probability of NOT calling a person from neighborhood

= 1 - probability of calling a person from his neighborhood

$= 1 - (\frac{4}{5}) = \frac{5-4}{5} = (\frac{1}{5})$

⇒P( not E) = $(\frac{1}{5} )$

Hence, P(call a person not from his neighborhood) = $(\frac{1}{5} )$

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3 years ago

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The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the proba

padilas [110]

Answer:

A Poisson distribution, with λ=5.3

$P(x) = \frac{\lambda^{x} *e^{-\lambda}}{x!}$

Step-by-step explanation:

For this type of random variables, a Poisson distribution is the most adecuate.

If the number of occurrences in ten minutes is 5.3, we can define the parameter λ=5.3 and the probability function as:

$P(x) = \frac{\lambda^{x} *e^{-\lambda}}{x!} =\frac{5.3^{x} *e^{-5.3}}{x!} \approx\frac{0.005*5.3^{x}}{x!}$

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3 years ago