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gizmo_the_mogwai [7]
3 years ago
12

Help please!!! i’ve been stuck on this for days!

Mathematics
1 answer:
Snezhnost [94]3 years ago
3 0

Answer:

Step-by-step explanation:

What is the full question?

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50 points plus brainliest please help screenshot provided
never [62]

Answer:

\textsf{(a)} \quad (3x)^{\circ}+(x+14)^{\circ}=90^{\circ}

\textsf{(b)} \quad m \angle 1=\boxed{57}\:^{\circ}

       m \angle 2=\boxed{33}\:^{\circ}

Step-by-step explanation:

From inspection of the given diagram:

  • m \angle 1=(3x)^{\circ}
  • m \angle 2=(x+14)^{\circ}

<h3><u>Part (a)</u></h3>

A right angle is 90° and is represented by the ∟ symbol.

To find x, <u>equal</u> the sum of the angles to 90° and solve for x:

\implies m \angle 1+m\angle2=90^{\circ}

\implies (3x)^{\circ}+(x+14)^{\circ}=90^{\circ}

\implies 3x+x+14=90

\implies 4x+14=90

\implies 4x+14-14=90-14

\implies 4x=76

\implies 4x \div 4=76 \div 4

\implies x=19

<h3><u>Part (b)</u></h3>

To find the degree measure of each angle, substitute the found value of x into the expression for each angle.

\implies m \angle 1=(3 \cdot 19)^{\circ}=57^{\circ}

\implies m \angle 2=(19+14)^{\circ}=33^{\circ}

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1 year ago
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