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9966 [12]
3 years ago
9

The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –2/3x + 6. What is the point-slope f

orm of the equation for this line?
y – 3 = –2/3(x + 8)
y + 3 = –2/3(x – 8)
y + 8 = –2/3(x – 3)
y – 8 = –2/3(x + 3)
Mathematics
2 answers:
balu736 [363]3 years ago
7 0

Answer:

I think that the answer is D

Kryger [21]3 years ago
3 0
Y = -2/3x + 6....the slope here is -2/3

y - y1 = m(x - x1)
slope(m) = -2/3
(-3,8)....x1 = -3 and y1 = 8
now we sub
y - 8 = -2/3(x - (-3) =
y - 8 = -2/3(x + 3) <===

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2 years ago
The slope of a line is -1/3, and the y-intercept is 10/3. What is the equation of the line written in general form?
Y_Kistochka [10]
The answer is:  [B]:  " x  + 3y + 10 = 0 " .
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Explanation:
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Note the equation for a line; in 'slope-intercept form':  "y = mx + b" ;
 
   in which "y" is isolated alone, as a single variable, on the left-hand side of the equation;
                "m" = the slope of the line; and is the co-efficient of "x" ;
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So, given the information in this very question/problem:
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slope = m = (-1/3) ; 
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And we can write the equation of the line; in "slope-intercept form"; that is:
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  " y = mx + b " ;  as:
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   " y = (-1/3)x + (10/3) " ;
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Now, the problem asks for the equation of this line; in "general form";  or "standard format";  which is:
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So; given: 
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 " y = (-1/3)x + (10/3) " ;
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  →  3* { y = (-1/3)x + (10/3) } ;

  →  3y = -1x + 10 ; 

        ↔  -1x + 10 = 3y ; 

Subtract "(3y)" from each side of the equation:
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            -1x + 10 − 3y = 3y − 3y ;

to get: 

-1x + 10 − 3y = 0 ; 

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