I want to know the work of this, like the process. Please

Mathematics

1 answer:

pogonyaev4 years ago

3 0

In this question, you know that the machine packs $\frac{2}{3}$ of a box every $\frac{1}{2}$ of a minute. Since it is constant, you simply have to double the half a minute to a full minute and then also double the rate to get $\frac{4}{3}$ boxes packed per minute. And $\frac{4}{3}$ is equal to $1\frac{1}{3}$

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Can some one help me with 0.38 as a fraction

Fofino [41]

Answer: 38/100

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3 0

3 years ago

Read 2 more answers

Consider the system of equations:

AVprozaik [17]

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Since, we know that in Elimination method we have to first the value of "x" or either "y". For that we have to multiply a number which makes the both equation's "x" or "y" equal so that we cut cancel it and find the solution.

Here's an example:

Like, in here

Equation 1: - 2x + 3y = 9

Equation 2: - 8x - 7y = 10

We can see that in "Equation 1" the first number is "- 2x" and in "Equation 2" the first number is "-8x". So, what we do in Elimination method is that we have to make the first number of both the equations equal or same.

Eg:

- 2x + 3y = 9.

- 8x + 7y = 10--(ii)

Now,we can see that in "Equation 2" the first number is "8x" whereas in "Equation 1" the first number is "-2x". We have to multiply with any number that makes the both the first number of equation is same.