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4 years ago

Which of the following represents a compound?

Chemistry

2 answers:

EastWind [94]4 years ago

8 0

Answer:

H₂O

Explanation:

Compound consists of combinations of elements. H (Hydrogen) is an element. O-16 and H-3 are stable isotopes of O (Oxygen) and H (Hydrogen), which are elements. H₂O is compound formed by two elements: Hydrogen and Oxygen.

kifflom [539]4 years ago

6 0

Answer:

B) H2O

Explanation:

Compound is a pure substance composed of two or more different atoms chemically bonded to one another. Among all choices only H₂O is composed of two atoms, and other choices are composed of only one atom. H₂O is the pure substance composed of chemically bonded two atoms (hydrogen atoms and oxygen atom).

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The mass of an atom of element x is equivalent to the total mass of 7 hydrogen atoms.

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Answer:

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Explanation:

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3 years ago

What do the colors of light combine to make _______________ light.

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3 years ago

Hands are very cold and the cup is very hot, heat energy transfers from the cup to her hands because

photoshop1234 [79]

Heat flows from a region of greater potential to lower potential?

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3 years ago

Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh

Dima020 [189]

Answer: The $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

Explanation:

For the given chemical reaction:

$2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)$

Half reactions for the given cell follows:

Oxidation half reaction: $ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V$ ( × 2)

Reduction half reaction: $Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=1.36-(0.954)=0.406V$

To calculate standard Gibbs free energy, we use the equation:

$\Delta G^o=-nFE^o_{cell}$

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

$E^o_{cell}$ = standard cell potential = 0.406 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J$

Hence, the $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

4 0

3 years ago

What is the effect of this??

a_sh-v [17]

Answer:

Explanation:

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7 0

3 years ago

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