The equilibrium constant for this reaction at 350°C is determined as 5.85.
<h3>Concentration of each component</h3>
concentration of bromine, C(Br) = 0.6 mol/1 = 0.6
concentration of iodine, C(I) = 1.6 mol/1 = 1.6
<h3>Create an ICE table</h3><h3>What is ICE table?</h3>
An ICE table is a tabular system of keeping track of changing concentrations in an equilibrium reaction.
ICE is an abbreviation that stands for initial, change, equilibrium.
Create ICE table for the reactants and products formed;
Br2(g) + I2(g) ↔ 2IBr(g)
I 0.6 1.6 0
C -1.19 -1.19 1.19
E 0.6 - 1.19 1.6 - 1.19 1.19
E = -0.59 0.41 1.19
<h3>Equilibrium constant </h3>
The equilibrium constant is calculated as follows;
KC = [IBr]²/[Br][I]
KC = (1.19²) / (0.59 x 0.41)
KC = 5.85
Thus, the equilibrium constant for this reaction at 350°C is determined as 5.85.
Learn more about equilibrium constant here: brainly.com/question/19340344
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