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2 years ago

When an atom loses and electron. The excess charge comes from protons

Chemistry

1 answer:

ch4aika [34]2 years ago

8 0

Answer:

If it loses an electron, it becomes positively charged and is known as a cation.

Explanation:

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K2so4 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.450 m k2so4 solution.

amid [387]

Answer:

Conc. of K+ ions = 0.90 M
Coc. of SO4∧-2 = 0.45 M

Explanation:

Data Given:

Conc. of H2SO4 = 0.450

As sulphoric acid is a strong electrolyte, it completely dissociate into ions.

H2SO4 ⇆ 2K+ + SO4∧-2

.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.

K2SO4 : K+ K2SO4 : SO4∧-2

1 = 2 1 = 1

0.450 = 2× 0.450 = 0.90 0.450 = 0.450×1 = 0.450

Result:

Conc. of potassium ion will be 0.90M

Coc. of sulphate ions will be 0.45 M

8 0

3 years ago

An athlete can run 4 m/s. How far can she run in 3 minutes?

shutvik [7]

Answer:

720

Explanation:

4 m/s

60 seconds

= 180 seconds

3 minutes

4 m/s

= 720 m/s

180 seconds

5 0

3 years ago

A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50-L container of cold water, what woul

gayaneshka [121]

Answer:

10°C

Explanation:

Heat gain by water = Heat lost by the slice of pizza

Thus,

$m_{water}\times C_{water}\times \Delta T=Q$

For water:

Volume = 50.0 L

Density of water= 1 kg/L

So, mass of the water:

$Mass\ of\ water=Density \times {Volume\ of\ water}$

$Mass\ of\ water=1 kg/L \times {50.0\ L}$

Mass of water = 50 kg

Specific heat of water = 1 kcal/kg°C

ΔT = ?

For slice of pizza:

Q = 500 kcal

So,

$50\times 1\times \Delta T=500$

ΔT = 10°C

Increase in temperature = 10°C

3 0

3 years ago

in general, as the temperature increases, the solubility of gases in water ____ and the solubility of most solids in water___

saul85 [17]

Answer:

in general, as the temperature increases, the solubility of gases in water decreases and the solubility of most solids in water increases.

4 0

2 years ago

If aluminum is diffused into a thick slice of silicon with no previous aluminum in it at a temperature of 1100˚C for 8 hours, wh

RideAnS [48]

Answer:

8.354 nanometers

Explanation:

To treat a diffusive process in function of time and distance we need to solve 2nd Ficks Law. This a partial differential equation, with certain condition the solution looks like this:

$\frac{C_{s}-C{x}}{C_{s}-C_{o}}=erf(x/2\sqrt{D*t})$

Where Cs is the concentration in the surface of the solid

Cx is the concentration at certain deep X

Co is the initial concentration of solute in the solid

and erf is the error function

Then we solve right side,

$\frac{C_{s}-C{x}}{C_{s}-C_{o}}=\frac{1018atoms/cm3-1016atoms/cm3}{1018atoms/cm3}=0.001964$

And we need to look up the inverse error function of 0.001964 resulting in: 0.00174055

Then we solve for x:

$x=0.00174055*2*\sqrt{D*t} =0.00174055*2*\sqrt{2*10^{-12}cm^{2}/s*8h*3600s/h}=8.35464*10^{-7}cm$

6 0

3 years ago