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leva [86]
3 years ago
10

Give me answer please don't skip

Mathematics
2 answers:
Kay [80]3 years ago
5 0

Step-by-step explanation:

Th value of ab is 21

Explanation is in the attachment

hope it is helpful to you ☺️

thank you for giving me a chance to answer your question

spin [16.1K]3 years ago
4 0

Answer:

ab = 21

Step-by-step explanation:

(a - b)^2 = (a^2 + b^2 ) - 2ab\\\\4^2 = 58 - 2ab\\\\16 - 58 = - 2ab\\\\- 42 = - 2ab\\\\ab = \frac{-42}{-2} = 21

You might be interested in
The base of an isosceles triangle is 5 and it's perimeter is 11. The base of a similar isosceles triangle is 10.What is the peri
Andreas93 [3]

Answer: the perimeter of the larger triangle is 22 units

Step-by-step explanation:

The diagram of both triangles is shown in the attached photo. The isosceles triangles are triangle ABC and triangle DEF

Perimeter of triangle ABC = 11

For an isosceles triangle, the other two sides are equal. If one equal side is x, then the sum of the two equal sides is x+x = 2x

Perimeter of triangle = sum of the lengths of the 3 sides. Therefore,

11 = 5 + 2x

2x = 11-5 = 6

x = 6/2 = 3

The base of the similar triangle is 10. It means that it is 2 times the base of the smaller triangle. That means the scale factor is 2. Therefore,

If the perimeter of the small triangle is 11, the Perimeter of the larger triangle will be 2 × perimeter of the smaller triangle. This becomes

2 × 11 = 22 units.

It can also be determined by adding the length of each side

3×2 + 3×2 + 5×2 = 6+6+10 = 22 units

5 0
3 years ago
Read 2 more answers
Factorize the following<br> 4x+16y+24z
FrozenT [24]
  • 4x + 16y + 24z
  • = 4(x + 4y + 6z)

<u>Answer</u><u>:</u>

<u>4</u><u>(</u><u>x </u><u>+</u><u> </u><u>4</u><u>y</u><u> </u><u>+</u><u> </u><u>6</u><u>z</u><u>)</u>

Hope you could understand.

If you have any query, feel free to ask

6 0
2 years ago
Twenty-seven is<br>% of 60<br>help mee asap​
jok3333 [9.3K]

Answer:  The answer is:  " <u> </u><u>45 </u>  % "  .    

________________________________________________

               →    " Twenty-seven is <u> 45 </u> % of 60. "

________________________________________________

Step-by-step explanation:

________________________________________________

The question asks:

 " 27 is what % {percentage] of 60 " ?  ;

________________________

So:  " 27 =  (n/100) * 60 " ;  Solve for "n" ;

________________________________________________

Method 1:

________________________________________________

  →   (n/100) * 60 = 27 ;

Divide each side by 60 :

 →   [ (n/100)  * 60 ] / 60 = 27 /60 ;

to get:

 →    (n/100) = 27/60 ;

Now:  Cross-factor multiply:

 →  60n = (27)*(100) ;

to get:

 → 60n = 2700 ;

Divide each side by "60" ;

→  60n = 2700/ 60 ;

to get:  n = 45 ;

________________________

 →  The answer is:  45 % .    

   →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Method 2:

________________________________________________

The question asks:

 " 27 is what % {percentage] of 60 " ?

________________________

To solve this problem:

Rephrase this question as:

________________________

" 27 is 60% of what number ? "

 →  The answer will be the same!

________________________

→  27 = (60/100)* n ;   Solve for "n" ;

Multiply each side of the equation by "100" ; to eliminate the fraction:

→  100 * 27 = 100 * [ (60/100)* n ] ;

 to get:

   →   2700 = 60n ;

↔  60n = 2700 ;

Divide Each Side of the equation by "60" ;

    →   60n/60 = 2700 / 60 ;

to get:  n = 45 ;

________________________________________________

→  The answer is:  45 % .    

       →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Method 2:  Variant 1 of 2:

________________________________________________

When we have:

→  27 = (60/100)* n ;   Solve for "n" ;

________________________

Note that:  "(60/100) = (60÷ 100) = (6 ÷ 10)" ;   since:  in "(60/100)" ;  the "zero" from the "<u>numerator</u>" cancels out;  <u>And</u>:  the "last zero" in "100" — from the "<u>denominator</u>" cancels out;  since we are dividing "each side" of the fraction by "10" ;

  →   "(60÷10) / (600÷10)"  =  " 6/10 " ;  

  →   " (6/10)" ; that is;  "six-tenths"} ;  

  →     can be represented by:  " 0.6 " ;

  →  {by convention;  but specifically, here is the explanation} — as follows:

________________________

  →   "(6/10)" =  " (6 ÷ 10) " ;  

<u>Note</u>:  When dividing a number by "10" ;  we take the original number; and move the decimal point to the left; & then we rewrite that number as the "answer".  

<u>Note</u>:  When multiplying or dividing by a positive, non-zero integer factor of "10" that has at least 1 (one) "zero" after that particular factor of "10".  We can get the answer by taking the original number & moving the decimal point the number of spaces as designated by the number of zeros following the particular [aforementioned factor of "10".].

We move the decimal point to the right if we are multiplying;  and to the left  if we are dividing.  In this case, <u>we are dividing</u> "6" by "10 " :

 →  " 6   ÷  10  =  ? " ;  

 →  " 6.  ÷ 10 =  ? " ;

   We take the: " 6. " ;  and move the decimal point "<u>one space backward [i.e. "to the left</u>"];  since we are <u>dividing by "</u><u>10</u><u>"</u> ;

 →  to get:  " .6 " ;  & we rewrite this value as "0.6" in a rewritten equation:

________________________

So; we take our equation:

→  27 = (60/100)*n ;  And rewrite—substituting "0.6" for

"(60/100)"— as follows:

________________________

→  27 = (0.6)n ;  ↔ (0.6) n = 27 ;

Multiply each side of the equation by "10" ; to eliminate the decimal:

   →  10 * [ (0.6)n ]  = 27 * 10 ;

to get:

  →  6n = 270 ;

Divide each side of the equation by "6" ; to isolate "n" on one side of the equation; & to solve for "n" ;

 →  6n / 6  =  270 / 6 ;

to get:   n = 45 ;

________________________________________________

→  The answer is:  45 % .    

      →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Method 2 (variant 2 of 2):

________________________________________________

We have the equation:  27 = (60/100)* n ;   Solve for "n" ;

________________________

<u>Note</u>:  From Method 2 (variant) 1 of 2— see above):

________________________

<u>Note</u>:  Refer to the point at which we have:

________________________

→   " {  (60÷10) / (600÷10)"  =  " (6/10) " ;  that is;  "six-tenths"} ;

________________________

Note that the fraction— "(6/10)" ;  can be further simplified:

→  "(6/10)" =  "(6÷2) / (10÷2)" = "(3/5)" ;

Now, we can rewrite the equation;

→ We replace "(60/100)" ;  with:  "(3/5)" :

    →  27 = (3/5)* n ;   Solve for "n" ;

↔ (3/5)* n = 27 ;  

↔    (3n/5) = 27 ;

Multiply Each Side of the equation by "5" ;

→  5* (3n/5) = 27 * 5 ;  

to get:

→   3n = 135 ;

Divide Each side of the equation by "3" ;  to isolate "n" on one side of the equation;  & to solve for "n" ;

→  3n / 3 = 135 / 3  ;

to get:   n = 45 ;

________________________________________________

 →  The answer is:  45 % .    

       →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Hope this answer is helpful!

        Wishing you the best in your academic endeavors

           — and within the "Brainly" community!

________________________________________________

7 0
2 years ago
Read 2 more answers
The graph shows a probability distribution. What is P(1.5 ≤ X ≤ 3)? Enter your answer, as a decimal, in the box.
Bumek [7]
The probability from 1.5 ≤ x ≤ 3 can be calculated by dividing the Area from x=1.5 to x=3 by the total Area of the distribution. 

The given distribution is rectangular shaped, so its Area will be = Length x Width = 1 x 3 = 3 square units

From x = 1.5 to x = 3, the length is 1.5 and width is 1. So the area between these two intervals = 1.5 square units.

Thus, <span>P(1.5 ≤ X ≤ 3) = 1.5/3 = 0.5
</span>
5 0
2 years ago
If you can answer this question you'll get brainliest.
igomit [66]

Answer:

Volume = 66 cm³

Step-by-step explanation:

Area of the oblique triangular prism = Area of the triangular base × Vertical height from the base

From the figure attached,

Area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height of the right triangle})

                                             = \frac{1}{2}(3)(4)

                                             = 6 cm²

Vertical height of the given oblique prism = 11 cm

Volume of the given oblique prism = 6 × 11

                                                          = 66 cm³

4 0
3 years ago
Read 2 more answers
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