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yulyashka [42]
3 years ago
7

PLEASE HELP THIS IS URGENT

Mathematics
2 answers:
Lisa [10]3 years ago
6 0
X= 1, x = 5

-3|x - 3| = -6
———— —– divide both sides by -3
-3 -3 and remove the bars

x - 3 = 2
+3 +3
—————
x = 5⭐️

-3|1-3|➡️-3|-2|= -6
ICE Princess25 [194]3 years ago
4 0

Answer:

A. x = 1, x = -1

Step-by-step explanation:

Given the inequality

−3|x − 3| = −6

The equation will give us two solutions due to the nodulus sign. The modulus sign means that the function x- 3 can take both positive and negative value.

If |x-3| is positive, we have:

-3(x+3) = -6

-3x-9 = -6

Moving -9 to the other side:

-3x = -6-(-9)

-3x = -6+9

-3x = 3

x = 3/-3

x = -1

Similarly if |x-3| is negative, we have:

-3{-(x-3)} = -6

-3(-x+3) = -6

3x-9 = -6

3x = -6+9

3x = 3

x = 3/3

x = 1

The solutions are x = -1 and x = 1

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yawa3891 [41]

Answer: Statistic.

Step-by-step explanation: Statistic are used to refer to numerical measurement pertaining to a sample. A sample refers to a subset of members chosen from a population, which means a smaller representation of the larger group. Hence, in the scenario above, the population is the entire seniors which makes up the group. While the sample is the subset of seniors drawn from the whole. Hence, statistical measures calculated or derived from the sample is called statistic. Hence, the 25% obtained is a statistic.

3 0
3 years ago
Solve the linear inequality −6x+5>−1
Leto [7]
The answer to this question is:

x<1
7 0
3 years ago
What is the approximate area of the unshaded region under the standard normal curve below? Use the portion of the standard norma
Harlamova29_29 [7]

The approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

It is given that the standard normal curve shows the shaded area in the curve.

It is required to find the approximate area of the unshaded region under the standard normal curve.

<h3>What is a normal distribution?</h3>

It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.

In the curve showing the shaded region area between:

\rm P(1 < Z < 2)

First, we calculate the shaded region area:

From the data given the value of Ф(1) = 0.8413.

P(Z<1)  = 0.8413  and

P(Z<2) =  0.9772

The area of the shaded region:

= P(Z<2) - P(Z<1)

=  0.9772 - 0.8413

= 0.1359

The area of the unshaded region:

= 1 - The area of the shaded region  ( because the curve is symmetric)

= 1 - 0.1359

= 0.8641 ≈ 0.86

Thus, the approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

Know more about the normal distribution here:

brainly.com/question/12421652

4 0
2 years ago
When studying radioactive material, a nuclear engineer found that over 365 days,
Gnom [1K]

Answer:

a) The mean number of radioactive atoms that decay per day is 81.485.

b) 0% probability that on a given day, 50 radioactive atoms decayed.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\lambda is the mean in the given interval.

a. Find the mean number of radioactive atoms that decayed in a day.

29,742 atoms decayed during 365 days, which means that:

\lambda = \frac{29742}{365} = 81.485

The mean number of radioactive atoms that decay per day is 81.485.

b. Find the probability that on a given day, 50 radioactive atoms decayed.

This is P(X = 50). So

P(X = 50) = \frac{e^{-81.485}*(81.485)^{50}}{(50)!} = 0

0% probability that on a given day, 50 radioactive atoms decayed.

5 0
3 years ago
3 x 5 + 9(2+ 13)
san4es73 [151]
It hase to be le letter c
3 0
3 years ago
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