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3 years ago

By graphing the system of constraints, find the values of x and y that maximize the objective function.

1 answer:

6 0

The easiest method to solve problems like this is to graph the inequalities given and shade the regions that make them true. When you have properly shaded all of the regions, you will find that you have a region which is bounded on all four sides by one of the inequalities, and then you can find the x and y values which correspond to the vertices of the shaded region.

You didn't provide a function that you are trying to maximize in this example, but the idea is that you take all of the (x,y) points which correspond to the vertices and plug them into your objective function. The one which produces the largest value maximizes it (it is a similar process for minimizing it, but you'd be looking for the smallest value). Let me know if you need more help than that, or would like me to work out the example you have provided (I will need an objective function for it though).

You might be interested in

The linear function f i with values f(-1) = 10 and f(5) = -1 is f(x)

zhenek [66]

Answer:

Use the two points to compute the slope, m, then use one of the points in the form y=m(x)+b to find the value of b.

Explanation:

The equation for the slope, m, of a line is:

m=y1−y0x1−x0 [1]

The equation f(2)=−1 tells us that x0=2andy0=−1; substitute this into equation [1]:

m=y1−−1x1−2 [2]

The equation f(5)=4 tells us that x1=5andy1=4; substitute this into equation [2]:

m=4−−15−2 [3]

m=53

Substitute 53 for m into the equation y=m(x)+b

y=53x+b [4]

Substitute 2 for x and -1 for y and the solve for b:

−1=53(2)+b

b=−133

Substitute −133 for b in equation [4]:

y=53x−133 [5]

Check:

−1=53(2)−133
4=53(5)−133

−1=−1
4=4

Hope this helps

3 0

3 years ago

The difference in the x-coordinates of two points is 3, and the difference in the y-coordinates of the two points is 6. What is

Makovka662 [10]

To find the slope, use the rise/run technique with rise as the difference in y-coordinates and run as the difference in x-coordinates. So, the rise is 6 units and the run is 3 units in this situation. Now simply put it as a fraction: 6/3, which can be simplified to 2/1, or 2.

5 0

4 years ago

Read 2 more answers

A manager records the repair cost for 4 randomly selected TVs. A sample mean of $88.46 and standard deviation of $17.20 are subs

WINSTONCH [101]

Answer:

a) The critical value is $z = 2.575$ .

b) The 99% confidence interval for the mean repair cost for the TVs is ($66.31, $110.61).

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ . This is our critical value

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

a. Find the critical value that should be used in constructing the confidence interval.

The critical value is $z = 2.575$ .

b. Construct the 99% confidence interval. Round your answer to two decimal places.

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. So, in this problem

$M = 2.575*\frac{17.20}{\sqrt{4}} = 22.15$

The lower end of the interval is the mean subtracted by M. So it is 88.46 - 22.15 = $66.31

The upper end of the interval is the mean added to M. So it is 88.46 - 22.15 = $110.61

The 99% confidence interval for the mean repair cost for the TVs is ($66.31, $110.61).

5 0

3 years ago

Zion has a sink that is shaped like a half-sphere. The sink has a volume of . One day, his sink clogged. He has to use one of tw

VLD [36.1K]

Answer:

Step-by-step explanation:

Because Zion has the sink of a half sphere

8 0

3 years ago

A cube has a side of 5 cm. it has a mass of 250 grams. the density of the cube is

Marrrta [24]

Density = mass/volume

volume cube = side^3 = 5^3 = 125 cm^3, don't forget units!

Density = 250 grams / 125 cm^3 = 2 g/cm^3, with all the units

6 0

4 years ago