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Lady bird [3.3K]
3 years ago
9

What is the interquartile range of the set of data represented by the following box-and-whisker plot?

Mathematics
2 answers:
Valentin [98]3 years ago
7 0
In descriptive statistics, the interquartile range<span> (</span>IQR<span>), also called the midspread or middle 50%, or technically H-spread, is a measure of statistical dispersion, being equal to the difference between 75th and 25th percentiles... ~ wikipedia

according to Wikipedia and some quick mental math the answer would be four

four is the difference between 14 and 18 which are respectively the 25th and 75th percentiles.</span><span />
MissTica3 years ago
4 0

Answer:

4

Step-by-step explanation:

The interquartile range is the difference between the third quartile, Q3, and the first quartile, Q1.

In a box plot, Q1 makes up the left hand side of the box and Q3 makes up the right hand side of the box.  In this figure, Q1 is 14 and Q3 is 18; this makes the IQR

18-14 = 4

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Mr. Blue drove from Allston to Brockton, a distance of 105 miles. On his way back, he increased his speed by 10 mph. If the jour
andrew-mc [135]

Answer:

His original speed was 60 mph.

Step-by-step explanation:

The average speed formula is shown below:

speed = distance / time

For the first leg of the trip Mr. Blue drove at a speed of "x" mph, for a distance of 105 miles, therefore the time that took to complete the trip is:

time 1 = distance / speed

time 1 = 105 / x h

On the second leg of the trip Mr. Blue drove faster at a speed of "x + 10" mph, so the time it took him to complete the trip was 15 minutes less, therfore:

time 2 = time1 - (15/60) = (105/x) - 0.25 = (105 - 0.25*x)/x h

Applyint the time and speed from the second leg to the average speed formula we have:

x + 10 = {105/[(105 - 0.25*x)/x]}

x + 10 = 105*x/(105 - 0.25*x)

(x + 10)*(105 - 0.25*x) = 105*x

105*x + 1050 -0.25*x² - 2.5*x = 105*x

-0.25*x² -2.5*x + 1050 = 0 /(-0.25)

x² + 10*x - 4200 = 0

x1 = [-(10) + sqrt((10)² - 4*(1)*(-4200))]/2 = 60

x2 = [-(10) - sqrt((10)² - 4*(1)*(-4200))]/2 = -70

Since his speed couldn't be negative the only possible value was 60 mph.

5 0
3 years ago
Read 2 more answers
.33333 as a fraction
Varvara68 [4.7K]

Answer:

1/3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The average number of newspapers for sale in an airport stand is 15. SD is 6. The average age of the pilots is 36 and SD is 4. W
balu736 [363]

Answer:

The average age of pilots has a lower coefficient of variation, so it is the most consistent data set.

Step-by-step explanation:

The coefficient of variation is used to measure consistency of a data set. It is the standard deviation divided by the mean. The higher the coefficient of variation, the more variable, that is, the least consistent the data set is.

The average number of newspapers for sale in an airport stand is 15. SD is 6.

The consistency is:

C = \frac{6}{15} = 0.4

The average age of the pilots is 36 and SD is 4.

The consistency is:

C = \frac{4}{36} = 0.11

The average age of pilots has a lower coefficient of variation, so it is the most consistent data set.

4 0
3 years ago
F−1(−2) = <br><br> f(−4) = <br><br> f(f−1(−2)) =
Sauron [17]

need more information

7 0
3 years ago
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Are all of those questions I think it’s C
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2 years ago
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