Revenue: R(x) = 100x
Profit: P(x)= 3100 + 9x + 0.1x2 <span>(0 ≤ x ≤ 500)
</span><span>equalize the two equations
</span>100x=3100 + 9x + 0.1x2
0.1x2-91x+3100=0
<span>using graphic tools
x1=35.447----35
x2=874
the domain is </span>(0 ≤ x ≤ 500)
the value from which there are profits is 35 <span>pairs of cleats
</span>
Revenue: R(x) = 100x --------100*35=$3500
Profit: P(x)= 3100 + 9x + 0.1x2 -------3100+9*35+0.1*(35)2=$3537.5
Profit > Revenue up to the amount of 35 pairs of cleats
Answer:
The perimeter of the figure as a function of the number of triangles is 
.
Step-by-step explanation:
According to the diagram, we get the following facts:
i) For one triangle (
), the total perimeter is (
).
ii) For two triangles (
), the total perimeter is (
)
iii) For three triangles (
), the total perimeter is (
)
iv) For four triangles (
), the total perimeter is (
)
From these information we conclude that the equation that determines the perimeter of the figure as a function of the number of triangles is .
Answer:
-16 and -14
14 and 16
Step-by-step explanation:
Let's say x is the smaller integer and x+2 is the larger integer. Their product is 224.
x (x + 2) = 224
x² + 2x = 224
Complete the square and solve for x.
x² + 2x + 1 = 225
(x + 1)² = 225
x + 1 = ±15
x = -16 or 14
x + 2 = -14 or 16
So the integers are either -16 and -14, or 14 and 16.
Answer:
c = 1.29s + 2
Step-by-step explanation:
c represents the total cost
s represents the number of songs downloaded
1.29 represents the cost charged for every song downloaded
2 represents the initial cost to download the app
Connor has 14 quarters and 28 dimes.
Step-by-step explanation:
Given,
Worth of coins = $6.30 = 6.30*100 = 630 cents
We know that,
1 quarter = 25 cents
1 dime = 10 cents
Let,
Quarter = x
Dime = y
According to given statement;
25x+10y=630 Eqn 1
The number of dimes is 14 more than the number of quarters
y = x+14 Eqn 2
Putting value of y from Eqn 2 in Eqn 1
Dividing both sides by 35
Putting x=14 in Eqn 2
Connor has 14 quarters and 28 dimes.
Keywords: linear equation, substitution method
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