5/100's tortoise's life was spent above ground.
Hello!
Here are the steps to your problem:
3x + 5 = x - 3
3x -x = -3 -5
2x = -8
x = -4
I hope this helps you! Have a lovely day!
-Mal
The logs rules work "backwards", so you can condense ("compress"?) strings of log expressions into one log with a complicated argument. When they tell you to "simplify" a log expression, this usually means they will have given you lots of log terms, each containing a simple argument, and they want you to combine everything into one log with a complicated argument. "Simplifying" in this context usually means the opposite of "expanding".
There is no standard definition, in this context, for "simplifying". You have to use your own good sense. If they give you a big complicated thing and ask you to "simplify", then they almost certainly mean "expand". If they give you a string of log terms and ask you to "simplify", then they almost certainly mean "condense".
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Answer:
Step-by-step explanation:
x^2 + x^2 = 128 Normally you don't do this but rewrite the question
1x^2 + 1x^2 = 128
You actually do use 1 + 1 = 2 First time I've ever done that.
2x^2 = 128 Divide by 2
2x^2/2 = 128 / 2
x^2 = 64 Take the square root of both sides
sqrt(x^2)= sqrt(64)
x = 8
Answer:
a=5
b=-4
c=8
Step-by-step explanation:
