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Butoxors [25]
3 years ago
9

The solution to an any quality is giving in the same building notation as The solution to an inequality is giving in the set bui

lder notation as {x|x>2/3}. What is another way to represent the solution set?
Mathematics
1 answer:
Lostsunrise [7]3 years ago
8 0

<u>Options</u>

(A)\left(-\infty , \dfrac23\right]\\\\(B)\left(-\infty , \dfrac23\right) \\\\(C)(\frac23\right, \infty ) \\\\(D) [\frac23\right, \infty )

Answer:

(C)(\frac23\right, \infty )

Step-by-step explanation:

Given the solution to an inequality

{x|x>2/3}

The solution set does not include \dfrac23 , therefore, it must be open at the left. Recall that we use a curvy bracket ( to denote openness at the left.

Since x is greater than  \dfrac23 , the solution set contains all values of larger than  \dfrac23 up till infinity. Since infinity is an arbitrarily large value, we also use an open bracket at the right.

Therefore, another way to represent the solution {x|x>2/3} is:

(\frac23\right, \infty )

The correct option is C.

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1.
km=kilometers
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1 km=1000meters
so
1/2km= 1/2 times 1000=1000/2=500meters


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7 0
3 years ago
A farmhouse shelters 8 animals. Some are sheep and some are geese. Altogether there are 20 legs. How many of each animal are the
Novosadov [1.4K]

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I think they have 2, I could be wrong though

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Is (x+1)^2 equivalent to x^2 + 1? explain
Mademuasel [1]

Answer:

No.

Step-by-step explanation:

(x+1)^2=(x+1)(x+1)=x^2+x+x+1=x^2+2x+1

This is different from x^2+1.

Thus, they are not equivalent.

4 0
2 years ago
In 1898, L. J. Bortkiewicz published a book called The Law of Small Numbers, where using data he collected for twenty years, he
julia-pushkina [17]

Answer:

given : 0.61 per year

formula poisson probability : p(x=k)=xke-x/k!

(a) The parameter λ is the product of the rate per year and the number of years. The number of years is 1 year in this case.

λ=0.61×1=0.61

Evaluate the formula of the Poisson probability at k=0,1:

P(X=0)= 0!

(0.61)

0

e

−0.61

​

≈0.5434

P(X=1)=

1!

(0.61)

1

e

−0.61

​

≈0.3314

Add the corresponding probabilities:

P(X≤1)=P(X=0)+P(X=1)=0.5434+0.3114=0.8748

Use the complement rule:

P(X>1)=1−P(X≤1)=1−0.8748=0.1252

Note: The solution in the back of the book is the probability of at least one death instead of more than 1 death, thus the solution in the back of the book is not correct.

Step-by-step explanation:

this is prob wrong so im sorry in advance!

6 0
1 year ago
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