graph the linear equation. find three points that solve the equation, then plot on the graph -5x+2y=11
1 answer:
The equation given is -5x + 2y = 11
Write the equation in standard form for a straight line.
2y = 5x + 11
y = (5/2)x + 11/2
The slope is 5/2 = 2.5.
The y-intercept is (0, 11/2) or (0, 5.5)
At the x-intercept, y = 0. Therefore
-5x = 11
x = -11/5 = -2.2 is the y-intercept, that is (-2.2, 0)
When x = 1, obtain
y = (5/2)*1 + 11/2 = 8
The line has these three points that solve the equation:
(0, 5.5)
(-2.2, 0)
(1, 8)
The graph is shown below, with the three points.
Write the equation in standard form for a straight line.
2y = 5x + 11
y = (5/2)x + 11/2
The slope is 5/2 = 2.5.
The y-intercept is (0, 11/2) or (0, 5.5)
At the x-intercept, y = 0. Therefore
-5x = 11
x = -11/5 = -2.2 is the y-intercept, that is (-2.2, 0)
When x = 1, obtain
y = (5/2)*1 + 11/2 = 8
The line has these three points that solve the equation:
(0, 5.5)
(-2.2, 0)
(1, 8)
The graph is shown below, with the three points.
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