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sineoko [7]
2 years ago
5

What is 700 rounded to because i do not no it is very hard and i really need help and i really do not now how to round like it i

s really really hard so i really wish you will help me please
Mathematics
1 answer:
loris [4]2 years ago
7 0
700 rounded is just 700 since there’s no decimal and it’s a whole number it would stay 700 :)
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Simplify this expression 8n/17n
docker41 [41]
You can reduce the expression by cancelling out common factor n:

\frac{8n}{17n} =  \frac{8}{17}
4 0
2 years ago
Today’s cafeteria specials are a turkey sandwich and a pepperoni pizza. During 1st lunch, the cafeteria sold 70 turkey sandwiche
sveticcg [70]

Answer:

$4 and $3

Step-by-step explanation:

First, write out the equations as 70x + 29y = 367 and 70x + 45y = 415. Solve by using the elimination method by subtracting 70x from 70x. 45y minus 29y is equal to 16y. 415 minus 367 is 48. Divide 48 by 16, to get y is equal to get y is equal to three. Y represents pepperoni pizzas, so a pepperoni pizza costs $3. Plug a 3 into any equation for y and solve for x. 29 times 3 is 87. 367 minus 87 is 280. 280 divided by 70 is equal to 4, so x is equal to 4.

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2 years ago
The temperature, t, in Burrtown starts at 21°F at midnight, when h = 0. For the next few hours, the temperature drops 4 degrees
sweet-ann [11.9K]
In this case the temperature depends on the hour.  So temperature is your X and hour is your Y variable.  When h=0, x=0.   So the 21*C is you x=0 or y-int point.  

If we are trying to match the equation for a line of y=mx+b, 21*C=b.  

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Answer D.
6 0
2 years ago
Read 2 more answers
Gabby assumed she could sell 45 boxes of cookies by Friday, but she only sold 26 boxes. What was Gabby's percent error? ​
Agata [3.3K]

Answer:

73.07%

Step-by-step explanation:

Given that,

Actual value of sold cookies = 26

Assumed value of sold cookies = 45

We need to find Gabby's percent error. The percentage error in a value is given by :

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So,

\%=\dfrac{45-26}{26}\times 100\\\\=73.07\%

So, Gabby's percent error is equal to 73.07%.

4 0
2 years ago
Please help me for the love of God if i fail I have to repeat the class
Elena-2011 [213]

\theta is in quadrant I, so \cos\theta>0.

x is in quadrant II, so \sin x>0.

Recall that for any angle \alpha,

\sin^2\alpha+\cos^2\alpha=1

Then with the conditions determined above, we get

\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35

and

\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}

Now recall the compound angle formulas:

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta

\sin2\alpha=2\sin\alpha\cos\alpha

\cos2\alpha=\cos^2\alpha-\sin^2\alpha

as well as the definition of tangent:

\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}

Then

1. \sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}

2. \cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}

3. \tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}

4. \sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}

5. \cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}

6. \tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7

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\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2

\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2

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Because x is in quadrant II, we know that \dfrac x2 is in quadrant I. Specifically, we know \dfrac\pi2, so \dfrac\pi4. In this quadrant, we have \tan\dfrac x2>0, so

\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32

8. \sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}

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