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statuscvo [17]
3 years ago
14

Every integer is a divisor of itself. A proper divisor of an integer means a positive divisor other than the integer itself. For

example, the divisors of 8 are 1, 2,4, and 8, but the proper divisors of 8 are just 1,2, and 4.
What is the smallest positive integer whose proper divisors add up to more than the integer itself?
Mathematics
2 answers:
Kazeer [188]3 years ago
5 0
I believe it is 4 because it would be 2 and 2

algol [13]3 years ago
5 0
The correct answer is 4? :)
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What is the measure of XYZ?<br> А. 74°<br> В. 296°<br> с. 32°<br> D. 148°
LenaWriter [7]

Answer:

∠XYZ = 74°

Step-by-step explanation:

∠XYZ = \frac{1}{2} arcXZ

∠XYZ = \frac{1}{2} 148°

∠XYZ = 74°

8 0
3 years ago
Read 2 more answers
Multiple Choice
mihalych1998 [28]

Answer:

D is correct

Step-by-step explanation:

A graph of that sort will make a perfectly mirrored "V" shape, and with no offset, the bottom point will be on the y axis.  This means that the first equation will intercept the y axis at zero, the second will intercept the y-axis at -15.

"A" may seem correct also, as the second graph will intercept the x-axis at -15, but it is not complete, as it will intercept that axis at +15 as well.

7 0
3 years ago
Select the proper order from the least to the greatest 1/2 5/6 2/7 4/2
Olin [163]

Answer:

1/2, 2/7, 5/6, 4/2

Step-by-step explanation:

4 0
3 years ago
What all numbers whose absolute value is 6
GalinKa [24]

Answer:

6, -6

Explanation:

-----

3 0
3 years ago
The end points of a diameter of a circle are (6,2) and (-4,7).
motikmotik

Answer:

Step-by-step explanation:

The standard form equation of a circle with radius r is expressed as

( x − h )^2 + ( y − k )^2 =r ^2 ,

where r represents the radius

h and k are the coordinates of the center of the circle C( h , k )

To determine the coordinates at the center of the circle, the midpoint formula would be used. It is expressed as

[(x1 + x2)/2 , (y1 + y2)/2]

Midpoint of the circle =

(6 - 4)/2 , (2 + 7)/2 = (1, 4.5)

h coordinate of the center = 1

k coordinate of the center = 4.5

r^2 = (x - h)^2 + (2 - k)^2

r^2 = (6 - 1)^2 + (2 - 4.5)^2

r^2 = 5^2 + (- 2.5)^2 = 25 + 6.25

r^2 = 31.25

Substituting r^2 = 31.25, h = 1 and k = 4.5 into (x − h )^2 + ( y − k )^2 = r^2, the standard equation of the circle becomes

(x − 1 )^2 + ( y − 4.5 )^2 = 31.25

3 0
3 years ago
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