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4 years ago

Measure of arc JKM= ??

Mathematics

1 answer:

Sergio039 [100]4 years ago

8 0

Answer:

180°

Step-by-step explanation:

JM is the diameter of the circle with center L.

$\huge \red{ \boxed{\therefore m\widehat{(JKM)} = 180\degree}} \\$

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A researcher is interested in finding a 95% confidence interval for the mean number of times per day that college students text.

Oxana [17]

Complete Question

A researcher is interested in finding a 95% confidence interval for the mean number of times per day that college students text. The study included 210 students who averaged 28 texts per day. The standard deviation was 21 texts.

Round your answers to two decimal places.

A. The sampling distribution follows a [ Select ] ["F", "normal", "T", "Chi-square"] distribution.

B. With 95% confidence the population mean number of texts per day of is between [ Select ] ["24.92", "25.79", "27.37", "25.14"] and [ Select ] ["31.19", "31.20", "29.28", "30.86"] texts.

C. If many groups of 210 randomly selected students are studied, then a different confidence interval would be produced from each group. About [ Select ] ["5", "95", "1", "99"] percent of these confidence intervals will contain the true population mean number of texts per day and about [ Select ] ["95", "99", "5", "1"] percent will not contain the true population mean number of texts per day.

Answer:

a. With 95% confidence the population mean number of texts per day is between $I = 21.06$ and $I = 30.33$ texts.

If many groups of 132 randomly selected members are studied, then a different confidence interval would be produced from each group. About 95% percent of these confidence intervals will contain the true population number of texts per day and about 5% percent will not contain the true population mean number of texts per day.

Step-by-step explanation:

From the question we are told that

The sample size is $n = 102$

The population mean is $\mu = 25.7$

The standard deviation is $\sigma = 23.9$

Generally the standard error of mean is mathematically evaluated as

$\sigma_e = \frac{\sigma}{\sqrt{n } }$

substituting values

$\sigma_e = \frac{23.9}{\sqrt{102 } }$

$\sigma_e = 2.3665$

Given that the level of confidence is 95% then the level of significance will be

$\alpha = 100 -95$

$\alpha =$ 5%

=> $\alpha = 0.05$

Now the critical values of this level of significance is obtained from the critical value table as

$t_{n,\alpha } = t_{102,0.05} = 1.96$

Generally the 95% confidence interval is mathematically represented as

$I = \mu \pm t_{102, 0.05} * \sigma_e$

substituting values

$I = 25.7 \pm 1.96 *2.3665$

$I = 25.7 \pm 4.638$

$I = 30.33$ and $I = 21.06$

So the interval is

6 0

4 years ago

A passenger escalator travels from the first floor to the fifth floor a distance of 10 m in 10 seconds what is the escalator spe

Mumz [18]

It is presumed that the 10m is the vertical distance in 4 floors so 10meters divided by 10 seconds is 1m/second is the average speed of the escalator. Hard to add anything to this to make up to the required 40 words.

5 0

4 years ago

How do i divide 41 2/3 cups of flour into 4 7/12 cups

Hoochie [10]

We can do this from finding 2/3, and that equals 0.66_7 and 7/12 is 0.5833_ and we divide the whole thing. 41.66 and 4.5833 and we get 11

5 0

3 years ago

Find the perimeter and the area of the polygon with the given vertices

Nesterboy [21]

The answer is nine.

6 0

4 years ago

If WXY is equilateral and WZY is isosceles, find each missing measure.

timurjin [86]

Answer:

m∠1 = 60°

m∠2 = m∠4 = 39°

m∠3 = m∠5 = 21°

Step-by-step explanation:

ΔWXY is a equilateral angle,

Therefore, all angles of the the triangle are equal in measure.

m∠W + m∠X + m∠Y = 180°

3m∠W = 180°

m∠W = 60°

Since, ΔWZY is an isosceles triangle,

m∠3 = m∠5

m∠3 + m∠Z + m∠5 = 180°

m∠3 + 138° + m∠3 = 180°

2m∠3 = 180 - 138

m∠3 = 21°

Therefore, m∠3 = m∠5 = 21°

Since, m∠2 + m∠3 = 60°

m∠2 = 60 - 21

= 39°

Since, m∠4 + m∠5 = 60°

m∠4 = 60 - 21

= 39°

m∠1 = 60°

7 0

3 years ago

Read 2 more answers