To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.
Answer:
1
Step-by-step explanation:
1. Convert the mixed number to an improper fraction to match the rest of the problem (this just makes it easier for now, the answer will still be a mixed number)
-1 becomes
2. Re-write the new equation. When there is a "+" in front of a set of parentheses the expression doesn't change aside from removing the plus signs.
The new equation becomes
3. Calculate. Just work out the new expression.
The answer is
4. Convert to a simplified mixed decimal.
27 goes into 20 once with seven left over, making the answer 1
Answer:
Step-by-step explanation:
so first we need to find the height so by splitting the isosceles triangle into two right-angled triangles and then applying Pythagoras' Theorem to one of them.
We now know the height of the triangle and can use this to go back and find the area of the isosceles triangle.
area of triangle = x base x height
area of triangle = x 10 x 12
area of triangle = 60