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Montano1993 [528]
3 years ago
9

Write an equation of the line in point-slope form y-y_1=m(x-x_1) from the given point and slope.

Mathematics
1 answer:
valentina_108 [34]3 years ago
8 0

Answer:

The equation in point-slope form is y-6=2(x-4).

Step-by-step explanation:

We are given the slope and a coordinate pair of a line.

  • Slope: 2
  • Coordinate Pair (x, y): (4, 6)

Therefore, we can now label our coordinate pair and substitute our values into the formula. Our formula is:

\displaystyle y-y_1=m(x-x_1)

We can label our coordinate pairs with the (x_1, y_1) labeling method.

Therefore, since our two coordinates are:

  • x = 4
  • y = 6

We can label 4 as x₁ and 6 as y₁.

Then, we are able to determine <em>m</em>, or our slope.

  • m = 2

Now, let's set up our equation.

\displaystyle y - y_1 = m(x - x_1)\\\\y - 6 = 2(x - 4)\\\\y - 6 = 2x - 8\\\\y = 2x - 2

Therefore, our line is y = 2x - 2. However, the problem asks for it in point-slope form. So, this is exactly what we have in Step 2: y - 6 = 2(x - 4).

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Use the information given to enter an equation in standard form.
grin007 [14]

Answer:

6x - 5y = -5

Step-by-step explanation:

Your FIRST goal is to fill out y = mx + b with the values of m (your slope) and b (your y-intercept). First, find m by dividing the change in y in the two points given by their change in x. (43 - 31)/(35-25) = 12/10 = 6/5. Plug this in immediately for a "placeholder equation" of y = 6/5x + b, which you can plug either of your points into and solve for b.

43 = 6/5(35) + b

43 = 42 + b

1 = b

Your SLOPE-INTERCEPT equation is y = 6/5x + 1. However, you were asked for standard form. This means you must convert into ax + by = c, where a b and c are all whole numbers, and a is positive.

y = 6/5x + 1

-6/5x + y = 1

6/5x - y = -1

6x - 5y = -5, and this is your final answer.

Let me know if you need a more in-depth explanation on any part of this!

6 0
3 years ago
Sketch the triangle in the coordinate plane whose vertices are (0, -2), (2, 3).
Mars2501 [29]
B is the right thing 15 squints
4 0
3 years ago
The sum of two numbers is 3. Five times the larger number plus four times the smaller number is 29. Find the numbers
gulaghasi [49]
Let's have two numbers x (larger) and y (smaller). from the info above...

x + y = 3
5x + 4y = 29

so that means y=3 - x. we can sub this in
5x + 4(3-x) = 29
5x + 12 - 4x = 29
x = 17
then y=3-x=3-17=-14

so it's 17 and -14



7 0
3 years ago
Read 2 more answers
I'm having a hard time with this question so someone help please
bulgar [2K]

Answer:

  7.7 km

Step-by-step explanation:

This question is asking you to find the third side of a triangle in which two sides and an angle not between them are given. The law of sines provides the necessary relationships.

<h3>Law of Sines</h3>

The Law of Sines tells you that triangle side lengths are proportional to the sine of the opposite angle. For this triangle TPJ, the relation is ...

  t/sin(T) = p/sin(P) = j/sin(J)

We are given T=68°, p=5.2 km, t=7.5 km, and we are asked to find the length of j, the TP distance.

<h3>Setup</h3>

We know the sum of angles in a triangle is 180°, and the sine of an angle is equal to the sine of its supplement. This lets us fill in the Law of Sines equation like this:

  7.5/sin(68°) = 5.2/sin(P) = j/sin(68°+P) . . . . . solve for j

<h3>Solution</h3>

This can be solved in two steps. First, we find angle P, then we use that to find length j.

  sin(P) = 5.2/7.5 × sin(68°) ≈ 0.642847

  P = arcsin(0.642847) ≈ 40.0045°

Now, we can find j:

  j = 7.5 × sin(68° +40.0045°)/sin(68°) ≈ 7.693 . . . km

The distance from the tower to the plane is about 7.7 km.

__

<em>Additional comment</em>

We have used T, P, and J to refer to the vertices at the tower, plane, and jet.

The triangle can also be solved using the Law of Cosines. In that case, the missing side will be the solution to a quadratic equation with irrational coefficients.

3 0
2 years ago
What is the solution to the equation ?
Savatey [412]

Answer:

There is no solution of the system of equations.

Step-by-step explanation:

We are given two equations y = - 4 and y = 4 and are to find the solution to the equations.

Now, the straight line y = - 4 is parallel to the x-axis as the equation of straight lines that are parallel to the x-axis are given by y = c, where c is any constant value.

Again, the straight line y = 4 is parallel to the x-axis.

Therefore, y = - 4 and y = 4 two lines are parallel to each other and we know, parallel lines never intersect and hence there is no solution of the system of equations. (Answer)

6 0
3 years ago
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