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elena-s [515]
3 years ago
13

Emanuel has 745 pictures in his phone.His memory is getting full so he starts deleting 20 pictures every day.Define each variabl

e and write an algebraic expression to describe the number of pictures left on his phone after any given number of days.
Mathematics
2 answers:
Solnce55 [7]3 years ago
7 0

Answer:

745-20d

Step-by-step explanation:

Let d represent number of days.

We have been given that Emanuel starts deleting 20 pictures every day. The number of pictures deleted in d days will be 20d.

We have been given that Emanuel has 745 pictures in his phone. The number of pictures left after d days would be initial number of pictures minus number of pictures deleted in d days.

745-20d

Therefore, the expression 745-20d represents number of pictures left on Emanuel's phone after any given number of days.

IceJOKER [234]3 years ago
3 0
One variable is the amount of days. Lets call the amount of days D. Another variable is the amount of pictures left. Lets call this p. In this case, since Emanuel is deleting 20 pictures a day, and he has 745 picture to start with, the equation would be 745- 20D=p. 
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zloy xaker [14]

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Add  13  to each side:           n        =    1

================================

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6 0
3 years ago
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A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
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