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Karolina [17]
3 years ago
5

Given △ABC with AD¯≅DB¯, AE¯≅EC¯, DE=4 cm and you know that DE¯ is a __________. Therefore, BC= __________ cm.

Mathematics
2 answers:
satela [25.4K]3 years ago
8 0
DE is a midsegment, and BC= 8cm. It should be written as: midsegment, 8
damaskus [11]3 years ago
5 0
We need an image or something

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Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 35 problems. Each problem is worth either
fenix001 [56]

Answer:

x + y = 100

5x + 2y = 35

Step-by-step explanation:

3 0
3 years ago
sally gave her brother 3.95 in quarters and dimes. if the number of quarters is 6 more then the number of dimes, how many quarte
iragen [17]
Let q be the number of 25 cent coins.
Let d be the number of 10 cent coins.
0.25q+0.10d= 3.95...(1)
q-d=6...(2)

(2)->    q-d= 6
       q-d+d= 6+d
              q= 6+d...(2a)

(2a)-> (1)      0.25q+0.10d=3.95
              0.25(6+d)=0.10d= 3.95
           1.95+0.25d+0.10d= 3.95
                               0.35d= 3.95-1.5
                       0.35d/0.35= 2.45/0.35
                                      d= 7...(3)

(3)->(2)     q-d= 6
                 q-7= 6
                    q=6+7
                    q= 13
There are 13 quarters and 7 dimes.
7 0
3 years ago
Solve for X. Leave your answer in simplest radical form if necessary.
lord [1]

:) Brainliest?

Answer:

x = sqrt 2, y = 2

Step-by-step explanation:

45-45-90 triangles have a ratio of 1 : 1 : sqrt2

8 0
3 years ago
Read 2 more answers
What is the constant of proportionality
babymother [125]

Answer:

1/2

Step-by-step explanation:

1/2 x 1/2 = 1/4

3/4 x 1/2 = 3/8

1/1 x 1/2 = 1/2

5/4 x 1/2 = 5/8

(5/4 = 1 1/4)

5 0
3 years ago
Find the area of the Shaded region below in all of the smaller squares are identical in size
Lelechka [254]

Area of the shaded region = 80 in²

Explanation:

The outer diagram is a square

Area of the square = length × length

length = 12in

Area of the square = 12in × 12in

Area of the square = 144in²

There are 3 smaller squares in each row and column:

The length in each row and colum = 12

the length o fone small box = 12/3 = 4

Area of the smaller box = 4in × 4in = 16 in²

There are 4 boxes unshaded

Area of 4 unshaded boxes = 4 × 16 in² = 64in²

Area of the shaded region = Area of the outer box - area of the unshaded boxes

Area of the shaded region = 144 - 64

Area of the shaded region = 80 in²

7 0
1 year ago
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