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3 years ago

Z+(z-6)-2=-10 How donI solve this?

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

6 0

Answer:

z = -1

Step-by-step explanation:

Simplifying

z + (z + -6) + -2 = -10

Reorder the terms:

z + (-6 + z) + -2 = -10

Remove parenthesis around (-6 + z)

z + -6 + z + -2 = -10

Reorder the terms:

-6 + -2 + z + z = -10

Combine like terms: -6 + -2 = -8

-8 + z + z = -10

Combine like terms: z + z = 2z

-8 + 2z = -10

Solving

-8 + 2z = -10

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '8' to each side of the equation.

-8 + 8 + 2z = -10 + 8

Combine like terms: -8 + 8 = 0

0 + 2z = -10 + 8

2z = -10 + 8

Combine like terms: -10 + 8 = -2

2z = -2

Divide each side by '2'.

z = -1

Simplifying

z = -1

creativ13 [48]3 years ago

3 0

Answer:

z= -1

Step-by-step explanation:

Simplifying

z + (z + -6) + -2 = -10

Reorder the terms:

z + (-6 + z) + -2 = -10

Remove parenthesis around (-6 + z)

z + -6 + z + -2 = -10

Reorder the terms:

-6 + -2 + z + z = -10

Combine like terms: -6 + -2 = -8

-8 + z + z = -10

Combine like terms: z + z = 2z

-8 + 2z = -10

Solving

-8 + 2z = -10

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '8' to each side of the equation.

-8 + 8 + 2z = -10 + 8

Combine like terms: -8 + 8 = 0

0 + 2z = -10 + 8

2z = -10 + 8

Combine like terms: -10 + 8 = -2

2z = -2

Divide each side by '2'.

z = -1

Simplifying

z = -1

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Assume that adults have IQ scores that are normally distributed with a mean of 96 and a standard deviation of 15.7. Find the pro

astraxan [27]

Answer:

4.05% probability that a randomly selected adult has an IQ greater than 123.4.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 96, \sigma = 15.7$