Answer:
x=-61
Step-by-step explanation:
Answer:
12x-7=
Step-by-step explanation:
Just do -3 + -4 and 14x - 2x
Answer:
Null hypothesis: 
Alternative hypothesis: 
The alternative hypothesis for this case is that at least one mean is different from the others.
And the best method for this case is an ANOVA test.
Step-by-step explanation:
For this case we wnat to test if all the mean length of all face-to-face meetings and the mean length of all Zoom meetings are the same. So then the system of hypothesis are:
Null hypothesis: 
Alternative hypothesis: 
The alternative hypothesis for this case is that at least one mean is different from the others.
And the best method for this case is an ANOVA test.
Your answer would be:
The fourth option ---> 12