Answer:
Explanation:
CO₂ (aq) + H₂O (l) ⇄ H₂CO₃ (aq)
Equilibrium constant
Kc = [H₂CO₃] / [CO₂] [H₂O]
B )
PCl₃(g) + Cl₂(g) <--> PCl₅(g)
Kc = 24.3 .
[PCl₃] = .10M ,
[Cl₂] = 0.15 M
[PCl₅] = 0.60 M.
Qc = [PCl₅] / [PCl₃] [Cl₂]
= .60 / .10 x .15
= 40
Qc > Kc
Hence the reaction will proceed from left to right to reach equilibrium . It is so because the product concentration is more .
Option C is the right choice .
6 + 30 = 62 is literal equation.
Acting on the same object
Answer:
Mass = 8.46 g
Explanation:
Given data Mass of water produced = ? Mass of glucose = 20 g Mass of oxygen = 15 g
Solution:
Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6H₂O + 6CO₂
Number of moles of glucose:
Number of moles = mass/molar mass
Number of moles = 20 g/ 180.16 g/mol
Number of moles = 0.11 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 15 g/ 32 g/mol
Number of moles = 0.47 mol
now we will compare the moles of water with oxygen and glucose.
C₆H₁₂O₆ : H₂O
1 : 6
0.11 : 6/1×0.11 = 0.66
O₂ : H₂O
6 : 6
0.47 : 0.47
Less number of moles of water are produced by oxygen thus it will limit the yield of water and act as limiting reactant.
Mass of water produced:
Mass = number of moles × molar mass
Mass = 0.47 mol ×18 g/mol
Mass = 8.46 g
Explanation:
The molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated using the following formula:
Molarity = no of moles/volume
According to this question, a solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water.
no.of moles of CuSO4 = 35g ÷ 159.6g/mol
no. of moles of CuSO4 = 0.22 moles
Therefore; molarity of CuSO4 solution is calculated as follows:
M = 0.22 ÷ 0.25
M = 0.88M
Therefore, the molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.
Learn more about molarity at: brainly.com/question/12127540