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skelet666 [1.2K]
2 years ago
7

Which of these is an example of a literal equation?

Chemistry
2 answers:
Ganezh [65]2 years ago
8 0

Answer:

B

Explanation:

well if you calculate it,

12 - 9 = 3x

3 = 3x

x = 1

you can find the answer for x but in the other choices you have no inputs for the values therefore all of them are wrong, and D is just wrong because 6 + 30 doesnt equal 62

Papessa [141]2 years ago
4 0

6 + 30 = 62 is literal equation.

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Question 2 (Multiple Choice Worth 2 points)
faust18 [17]

Answer:

\pi r²  x h

Explanation:

A can is cylindrical in nature. Using the formula of the volume of the can, we can find this unknown volume.

The volume of cylinder is given as:

   Volume of a cylinder  = Area x height

  Volume of  a cylinder = \pi r²  x h

Therefore density of the can;

      Density  = \frac{mass}{volume}

6 0
2 years ago
how many grams of silver medal could be recovered from a reaction of 50 g silver nitrate and copper metal
Likurg_2 [28]

Answer:

Answer is: mass of copper is 127 grams.

Balanced chemical reaction: Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s).

m(Ag) = 432 g.

n(Ag) = m(Ag) ÷ M(Ag).

n(Ag) = 432 g ÷ 108 g/mol.

n(Ag) = 4 mol.

From chemical reaction: n(Ag) : n(Cu) = 2 : 1.

n(Cu) = 4 mol ÷ 2 = 2 mol.

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m(Cu) = 127 g

Explanation:

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One difference between d-glucose and l-glucose is
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<span>only D-glucose is found in disaccharides and polysaccharides.</span>
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A or D I think but go with A it makes more since
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Read 2 more answers
2) If I have an unknown quantity (# of moles) of gas at a pressure of 32 atm, a volume of 70 L, and a temperature of 25˚C. How m
astra-53 [7]

Answer:

91.5 mol

Explanation:

Volume of gas = 70 L

Temperature = 25°C

Pressure = 32 atm

Moles of gas  = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

25+273.15 = 298.15 K

By putting values,

32 atm × 70 L = n ×0.0821 atm.L /mol.K × 298.15 K

2240 atm.L = n ×24.48 atm.L /mol

n = 2240 atm.L / 24.48  atm.L /mol  

n = 91.5 mol

3 0
3 years ago
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