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AlladinOne [14]
3 years ago
10

The graph shows the altitude of a car as a driver descends down a mountain.

Mathematics
1 answer:
Sveta_85 [38]3 years ago
7 0

The rate of change represented by the graph is that the car drives down the mountain at a rate of 250 feets per hour.

The rate of change also called the gradient or slope is obtained using the relation :

Rate of change = change in y / change in x

Change in y = (y2 - y1)

Change in x = (x2 - x1)

From the graph :

y2 = 1500 ; y1 = 0

y2 = 1500 ; y1 = 0x2 = 6 ; x1 = 0

Hence,

Rate of change = (1500 - 0) / (6 - 0) = 1500 / 6 = 250

Learn more : brainly.com/question/2610134

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At the county fair, Darius can purchase 3 candy apples and 4 bags of peanuts for $11.33. He can purchase 9 candy apples and 5 ba
Ksenya-84 [330]
Let c represents the cost of a candy apple and b represents the cost of a bag of peanuts.

Darius can purchase 3 candy apples and 4 bags of peanuts. So his total cost would be 3c + 4b. Darius can buy 3 candy apples and 4 bags of peanuts in $11.33,so we can write the equation as: 

3c + 4b = 11.33   (1)

Darius can purchase 9 candy apples and 5 bags of peanuts. So his total cost would be 9c + 5b. Darius can buy 9 candy apples and 5 bags of peanuts in $23.56,so we can write the equation as: 

9c + 5b = 23.56   (2)

<span>Darius decides to purchase 2 candy apples and 3 bags of peanuts. The total cost in this case will be 2c + 3b. To find this first we need to find the cost of each candy apple and bag of peanuts by solving the above two equations.

Multiplying equation 1 by three and subtracting equation 2 from it, we get:

3(3c + 4b) - (9c + 5b) = 3(11.33) - 23.56

9c + 12b - 9c - 5b = 10.43

7b = 10.43

b = $1.49

Using the value of b in equation 1, we get:

3c + 4(1.49) = 11.33

3c = 5.37

c = $ 1.79

Thus, cost of one candy apple is $1.79 and cost of one bag of peanuts is $1.49.

So, 2c + 3b = 2(1.79) + 3(1.49) = $ 8.05

Therefore, Darius can buy 2 candy apples and 3 bags of peanuts in $8.05</span>
3 0
3 years ago
Sonic rolls up a slope at 9.4 m/s. after 3.0 he is rolling back down ay 7.4 m/s. how far up the hill is he at this time?
vovikov84 [41]
U= 9.4m/s
v= -7.4m/s (Negative sign because it is in the opposite direction as he is rolling back)
t= ?
s= ?
a= ?
Now, a= v-u/t
= -7.4-9.4÷3
=-5.6
By the second equation of motion.
s= ut+1÷2at*2 ( *2 is the power)
s= 9.4×3+1÷2×-5.6×3*2
= 28.2 +(-25.2)
=3
Therefore s or the distance travelled is 3m.


6 0
3 years ago
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