Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
i need more information like how much mai biked
Step-by-step explanation:
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Answer:
f(x) = 6x +1
Step-by-step explanation:
Differences in x-values (first row) are 1, 1, 1.
Differences in y-values (second row) are 6, 6, 6.
The constant ratio of differences (6/1) tells you the function is linear, and has a slope of m = 6/1 = 6.
Using the first point in the form ...
y = mx + b
we have ...
y = 6x + b
7 = 6·1 + b . . . . (x, y) = (1, 7)
1 = b . . . . . . subtract 6
Then the equation can be written ...
y = 6x +1
In functional form, this is ...
f(x) = 6x +1
I believe it is 8,000 grams :).
