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Shkiper50 [21]
3 years ago
5

What is the prime factorization of 44?

Mathematics
2 answers:
azamat3 years ago
8 0

Answer:the prime factorization of 44 is 22  and many more

Step-by-step explanation:

Read above

bulgar [2K]3 years ago
4 0

Answer:

2, 2 and 11. And guessing from the guy above me, many more!

Hope this helped!

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3x squared - 2 x y when x=2 and y = 5
ira [324]

the Answer is 4 do order of operations

7 0
3 years ago
Ginger spent $24 at the fair, which was three times the amount she spent last year at the fair. How much money did Ginger spend
zubka84 [21]

Answer:

She spent 8 dollars.

Step-by-step explanation:

24 divided by 3 is 8

5 0
3 years ago
A basketball player's total points scored for the season went from 158 to 231 over a period of 5 games. What was his scoring rat
Len [333]

Answer:

14.6

Step-by-step explanation:

(231 - 158) / 5 = 14.6

6 0
3 years ago
Please answer Thank you please answer hurry PLease
Alik [6]

Answer:

$(80.5x + 69)

Step-by-step Explanation:

Recall, distributive property of multiplication can simply be expressed as follows, x(y + z) = xy + xz or x(y - z). Where x, y, and z could be any number.

Now, let's use the distributive property to show the total costs of plants Gloria decides to buy as an expression and also simplify it.

Thus, Gloria buys:

4 ferns = 4(0.5x - 3) = 4(0.5x) - 4(3) = $(2x - 12)

2 palms = 2(10x - 2.50) = 2(10x) - 2(2.50) = $(20x - 5.00)

10 lilies = 10(5 + 0.25x) = 10(5) + 10(0.25x) = $(50 + 2.5x)

8 shrubs = 8(4.50 + 7x) = 8(4.50) + 8(7x) = $(36 + 56x)

Total cost of the plants = (2x - 12) + (20x - 5) + (50 + 2.5x) + (36+ 56x)

Open the parentheses and then simplify:

Total cost = 2x - 12 + 20x - 5 + 50 + 2.5x + 36 + 56x

= 2x + 20x + 2.5x + 56x - 12 - 5 + 50 + 36

Total cost = $(80.5x + 69)

5 0
3 years ago
Find the distance between the points (2, 7) and (-6, -2).
maw [93]

Answer:

Approximately 12.04 units.

Step-by-step explanation:

The find the distance between any two points, we can use the distance formula, which is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

We have the points (2,7) and (-6,-2). Let's let (2,7) be (x₁, y₁) and let's let (-6, -2) be (x₂, y₂). Substitute:

d=\sqrt{(-6-2)^2+(-2-7)^2

Subtract:

d=\sqrt{(-8)^2+(-9)^2

Square:

d=\sqrt{64+81}

Add:

d=\sqrt{145}

Approximate

d=\sqrt{145}\approx12.04

So, the distance between (2,7) and (-6,-2) is approximately 12.04 units.

And we're done!

7 0
3 years ago
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