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Nadusha1986 [10]
3 years ago
11

Three differnt way to wright 3,705.692

Mathematics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

3,705.692

Three thousand seven hundred and five thoudand six hundred and ninety two thousandths.

3 thousands, 7 hundreds, 5 ones, 6 tenths, 9 hundredths, 2 thousandths

Step-by-step explanation:

Simple math.

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What are the coordinates of the terminal point determined by T=20pi/3
Serga [27]

Answer:

t=5x=3049

Step-by-step explanation:

3 0
2 years ago
Solve the expression for x: (17 – 5) (x + 6) = 3x – 12
patriot [66]

(17-5)(x+6)-(3x-12)=0

12(x+6)-(3x-12)=0

12x-(3x-12)+72=0

12x-3x+12+72=0

9x+84=0

9x=-84

x=9+1/3






7 0
3 years ago
In the equation y = 2(x + 5), if x is increased by 3, then y is increased by
Zielflug [23.3K]
Y is increased by 6 because if you imagine x being 3 then y would = 16 but if you increase x by 3 making 6 then y would = 22 and 16 increased by 6 is 22
8 0
3 years ago
The diameter of a circle is 22 miles. What is the circle's area? Use 3.14 for pi.. Single choice.
Sonbull [250]

Answer:

379.94 mi²

Step-by-step explanation:

The area of a circle can be figured out with this formula: πr² (3.14 is π here, as it says in the directions).

We know the diameter is 22 miles. Divide that by 2 to get a radius of 11 miles.

The equation now becomes

3.14(11²)

11 squared is 121.

3.14(121)

I recommend splitting the 121 into 100, 20, and 1.

(3.14 * 100) + (3.14 * 20) + (3.14 * 1)

Multiply 3.14 by 100, 20, and 1.

314 + 62.8 + 3.14

Add 314 and 62.8.

376.8 + 3.14

Add 376.8 and 3.14

379.94 mi² is the area of a circle with a 22-mile diameter.

6 0
2 years ago
If angle EFH(5x+1)’ angle HFG(62 degrees) and angle EFG (18x+11) find each measurement
zloy xaker [14]

Answer:

∠EFH = 21°

∠HFG = 62°

∠EFG = 83°

Step-by-step explanation:

The diagram showing the angles has been attached to this response.

From the diagram, it can be deduced that;

Angle EFG = angle EFH + angle HFG

=> ∠EFG = ∠EFH + ∠HFG                -------------------(i)

From the question:

∠EFH = (5x + 1)°                    -------------(ii)

∠HFG = 62°                          -------------(iii)

∠EFG = (18x + 11)°                 -------------(iv)

<em>Substitute these values into equation (i) as follows;</em>

(18x + 11) = (5x + 1) + 62

=> 18x + 11 = 5x + 1 + 62

<em>Collect like terms and solve for x</em>

18x - 5x = 1 + 62 - 11

13x = 52

x = 4

Now, to get each measurement, substitute x = 4 into each of equations (ii) - (iv)

∠EFH = (5x + 1)°

∠EFH = (5(4) + 1)°

∠EFH = (20 + 1)°

∠EFH = 21°

∠HFG = 62°              [<em>Does not depend on x</em>]

∠EFG = (18x + 11)°

∠EFG = (18(4) + 11)°

∠EFG = (72 + 11)°

∠EFG = 83°

<u>Conclusion:</u>

∠EFH = 21°

∠HFG = 62°

∠EFG = 83°

8 0
3 years ago
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