$\frac{2}{3} x - \frac{5}{6} = - \frac{5}{12} x + \frac{1}{4} \\ \frac{2}{3}x + \frac{5}{12} x = \frac{1}{4} + \frac{5}{6} \\ \frac{8}{12} x + \frac{5}{12}x = \frac{3}{12} + \frac{10}{12} \\ \frac{13}{12} x = \frac{13}{12} \\ x = 1$

6 0

3 years ago

Read 2 more answers

If BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6, what are the values of x and AC?

Keith_Richards [23]

Answer: x=7 and AC = 44 unuts.

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other. (i)

Here in parallelogram ABCD , AC and Bd are diagonals intersecting at E.

BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6

Using (i)

$BE=\dfrac{BD}{2}\\\\2x+2=\dfrac{5x-3}{2}\\\\ 2(2x+2)=5x-3\\\\ 4x+4= 5x-3\\\\ 5x-4x=4+3\\\\ x= 7$

Now , AE = 4(7)-6 = 28-6 = 22

AC =2 AE = 2 (22) =44 units.

Hence, x=7 and AC = 44 unuts.

3 0

3 years ago

Find the slope <br> help with this please it’s due soon :)

GrogVix [38]

Undefined!! i hope this helps

4 0

2 years ago