All categories

3 years ago

Write the equation of a line that is perpendicular to y = 0 . 2 5 x − 7 y=0.25x−7y

1 answer:

3 0

write the equation of a line that is perpendicular to y=0.25x-7 and that ... 0. Check Marked as Best Answer. Its slope must be the negative.

You might be interested in

Here is 100 brain coins have a good day

Harrizon [31]

Answer:

omg thxxx and I hope you have a good day too :)))))))))

5 0

3 years ago

Prove each of these identities.

Virty [35]

<h3>Answer:</h3>

➲ ( 1 + sec x )( cosec x - cot x ) = tan x

Solving for L.H.S

$\implies\quad \sf{(1+sec\:x)(cosec\:x-cot\:x) }$

$\implies\quad \sf{ \left(1+\dfrac{1}{cos\:x}\right)\left(\dfrac{1}{sin\:x}-\dfrac{cos\:x}{sin\:x}\right)}$

$\implies\quad \sf{ \left(\dfrac{1+cos\:x}{cos\:x}\right)\left(\dfrac{1-cos\:x}{sin\:x}\right)}$

$\implies\quad \sf{ \left(\dfrac{1-cos^2 x}{cos\:x.sin\:x}\right)}$

$\implies\quad \sf{ \left( \dfrac{sin^2 x}{cos\:x.sin\:x}\right)}$

$\implies\quad \sf{ \left( \dfrac{sin\:x.\cancel{sin\:x}}{cos\:x.\cancel{sin\:x}}\right)}$

$\implies\quad \sf{\left( \dfrac{sin\:x}{cos\:x}\right) }$

$\implies\quad\underline{\underline{\pmb{ \sf{tan\:x}}} }$

➲ ( 1+ sec x )( 1- cos x ) = sin x. tan x

Solving for L.H.S

$\implies\quad \sf{ ( 1+ sec\:x)(1-cos\:x)}$

$\implies\quad \sf{\left(1+\dfrac{1}{cos\:x} \right) \left( 1-cos\:x\right)}$

$\implies\quad \sf{ \left(\dfrac{cos\:x+1}{cos\:x} \right)(1-cos \:x)}$

$\implies\quad \sf{\dfrac{1-cos^2 x}{cos\:x} }$

$\implies\quad \sf{\dfrac{sin^2x}{cos\:x} }$

$\implies\quad \sf{sin\:x.\left( \dfrac{sin\:}{cos\:x}\right) }$

$\implies\quad\underline{\underline{\pmb{ \sf{sin\:x.tan\:x}}} }$

7 0

3 years ago

Pls Help??

JulsSmile [24]

Answer:

false

Step-by-step explanation:

the formula for the area of a circle is πr^2

π=3.14

r= 1/2 of diameter = 6

3.14 x 6^2

=113.04cm2

5 0

3 years ago

A company purchased equipment and signed a 7-year installment loan at 9% annual interest. The annual payments equal $9,000. The

ANTONII [103]

First, we should apply the present value of annuity formula. It is $PV=A \frac{1- \frac{1}{(1+r)^{N}}}{r}$ and in this formula $\frac{1- \frac{1}{(1+r)^{N}}}{r}$ is the present value of annuity factor.

Then, we can find the present value of the annuity by writing that, $PV=9000 * 5.033 = 45297$

7 0

3 years ago

Read 2 more answers

Suppose a car's momentum is calculated to be 36000 . The mass of the car is 1,500 kg. What is the magnitude of the velocity of t

Ad libitum [116K]

Answer:

The magnitude of the velocity of the car is 24 m/s .

Step-by-step explanation:

Given : A car's momentum is calculated to be 36000 .

the mass of the car is 1500 kg.

To find: What is the magnitude of the velocity of the car.

Formula used:

Momentum =mass × velocity

Explanation:

We are given that momentum of the car =36000 .

Mass of the car = 1500 kg .

Plugging the given value in the above formula

Momentum =mass × velocity

36000 = 1500 × velocity

On dividing both side by 1500 we get ,

velocity = 24 meter/second

Therefore, The magnitude of the velocity of the car is 24 m/s .

4 0

3 years ago