Answer:
7.6 seconds
Step-by-step explanation:
To solve this problem we can use the following equation:
S = So + 113*t + at^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
In this problem, we have that S = 0, So = 65, Vo = 113 and a = -32 ft/s2 (The acceleration of gravity)
So we have that:
0 = 65 + 113t - 16t2
16t2 - 113t - 65 = 0
Using Bhaskara's formula, we have:
Delta = 113^2 + 4*65*16 = 16929
sqrt(Delta) = 130.11
t = (113 + 130.11) / (2*16) = 7.597 seconds
Rounding to nearest tenth, we have t = 7.6 seconds
Answer:
No. g(6) is undefined.
Step-by-step explanation:
A function is continuous when the left limit is equal to the right limit at a point, and the function is defined as the limit value at that point.
This function is not defined at x=6, so cannot be continuous there. (Also, the limit values from the different directions are different.)
Were are the problems i Cannot see them bro Sorry
Answer:
Step-by-step explanation:
Hi there!
Expand the parentheses
I hope this helps!
Graph B represents the equation.
