The statement which best describes the association between the variables X and Y is the <em>moderate positive association</em>. It is observable that the values of X and Y are increasing, however, not in a perfect manner as there are some minor deviations. But nonetheless, the direction is clear and the values are close to each other so they have a moderate positive association.
180- 113 = 67
180- 67= 113
<5= 67
<2=113
The second leftover expression is not o(a+b). It is 6(a + b). I have attached the correct question to depict that.
Answer:
The equivalent expressions are;
8a + 2 and 6a + 6b
Step-by-step explanation:
The two leftover expressions are given as;
2(4x + 1) and 6(a + b)
In algebra, equivalent expressions are simply those expressions which when simplified, give the same resulting expression as the initial one.
Thus simply means expanding or collecting like times to make it clearer.
Now, in our question, like terms have already been collected. This means that to find an equivalent expression, we will just expand the bracket.
Thus;
2(4x + 1) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;
8x + 2
Similarly,
6(a + b) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;
6a + 6b
Thus;
The equivalent expressions are;
8a + 2 and 6a + 6b
Answer:
She took $30.50 to the mall originally
Step-by-step explanation:
Let us solve the problem step by step
∵ She spent $5.25 on earrings
∵ The price of the shirt is 3 times the price of the earrings
∴ The price of the shirt = 3 × 5.25 = 15.75
∴ She spent $15.75 on the shirt
Find her total spending in the mall by adding the prices of earrings and the shirt
∴ She spent = 5.25 + 15.75 = 21
∴ She spent $21 on the mall
∵ She came home with $9.50
∵ She spent $21 on the mall
- Add them to find her original amount of money
∴ She took = 21 + 9.50 = 30.50
∴ She took $30.50 to the mall originally
Answer:
The final balance is £1,720.
The total compound interest is £520
you don't even to round it at all