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3 years ago

7

The areas of two similar rectangles are 180 ft.² and 320 ft.². What scale factor applied to the smaller rectangle will give the

larger rectangle?

1 answer:

grigory [225]3 years ago

8 0

The ratio of areas is the square of the scale factor, so that factor is
√(320/180) = 4/3

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Violet's Botanical Garden produced flowers throughout the year. A graph demonstrating how many flowers she produced over a 12-mo

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The domain represents a 12-month period of flower production

Step-by-step explanation:

The <em>domain</em> is <em>the horizontal extent of the graph</em>. Both the problem statement and the graph itself tell you that is a 12 month time period.

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Paisley is going to invest in an account paying an interest rate of 3.8% compounded monthly. How much would Paisley need to inve

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Step-by-step explanation:

Use the formula

$A(t)=P(1+\frac{r}{n})^{nt}$

Fill in the info we are given:

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3 years ago

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3 years ago

You operate a gaming Web site, www.mudbeast.net, where users must pay a small fee to log on. When you charged $3 the demand was

Doss [256]

Answer:

A) The linear relation between price and demand is:

$d=-550x+2750$

The revenue R is:

$R=-550x^2+2750x$

B) The profit functionP is:

$P=-550x^2+2750x-30$

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Step-by-step explanation:

We have a site where the number of log-ons depends on our monthly fee. A linear relation is established between the price (log-on fee) and the number of log-ons.

We have two points for this linear relationship:

At price x=3, the demand is d=1100.
At price x=2.5, the demand is d=1375.

We will model the relation:

$d=mx+b$

We can calculate the slope m as:

$m=\dfrac{\Delta d}{\Delta x}=\dfrac{d_2-d_1}{x_2-x_1}=\dfrac{1375-1100}{2.5-3}\\\\\\m=\dfrac{275}{-0.5}=-550$

Then, replacing one point in the linear equation, we can calculate the intercept b:

$d_1=mx_1+b\\\\1100=(-550)\cdot 3+b\\\\1100=-1650+b\\\\b=1100+1650=2750$

Then, the linear relation between demand and price is:

$d=-550x+2750$

The revenue R can be expressed as the multiplication of the price and the demand:

$R=x\cdot d=x(-550x+2750)=-550x^2+2750x$

If we have a fixed cost of $30 per month, the profit P is:

$P=R-FC=-550x^2+2750x-30$

We can maximize the profit by deriving the profit function and making it equal to zero.

$\dfrac{dP}{dx}=0\\\\\\\dfrac{dP}{dx}=-550(2x)+2750(1)=0\\\\\\-1100x+2750=0\\\\x=\dfrac{2750}{1100}=2.5$

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3 years ago

Answer with A B C D. Correct answer gets brainlest.

Sever21 [200]

Answer: B

Step-by-step explanation:

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