Answer:
17.9 m/s
Step-by-step explanation:
Volume of the slick = 0.5 x π r² h--------------------------------- (1)
Where r = radius of slick
h = thickness of slick, 10⁻⁶m
If 0.5m³ of oil leaked, then the radius of the semicircular slick can be calculated from equation (1)
V = 0.5 x π r² h
0.5= 0.5 x π x r² x 10⁻⁶
r² = 10⁶/ π
r = 10³/√π
dV/dt = πrh dr/dt + 0.5π r² dh/dt----------------------------------- (2)
Asumming the film thickness is constant , equation (2) becomes
dV/dt = πrh dr/dt-------------------------------- (3)
dV/dt = 0.1m³/day
r= 10³/√π
dr/dt= rate of expansion of the slick
Substituting into (3);
0.1 = π x 10³/√π x 10⁻⁶ x dr/dt
dr/dt = 0.1 x 10⁶/ ( π x 10³/√π)
= 17.9479 m/s
≅ 17.9 m/s
6god is watching from views
Answer:
100,000 days
Step-by-step explanation:
1,000,000 / 10 = 100,000 days.
Answer:
There is some inforrmation that is missing in this question. It should read:
A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .
Answers
Part 1. 0.02
Part 2. 0.0375
Explanation
The probability is a chance of an event happening. It is calculated as;
probability = (Number of favourable outcome)/(Number of available outcome)
Part 1
6 are chosen at random. If 4 are not defective, then 2 are defective.
P(at least 4 are not defective) = 4/40 × 2/10
= 1/10 ×1/5
= 1/50
= 0.02
Part 2
8 are chosen at random. If 3 are defective, the 5 are not defective.
P(3 are defective) = 3/40 × 5/10
= 15/400
= 3/80
= 0.0375
Step-by-step explanation:
Answer:
Table 3
Step-by-step explanation:
The third one.
We have the function
![h(x) = \sqrt[3]{-x+2}](https://tex.z-dn.net/?f=h%28x%29%20%3D%20%5Csqrt%5B3%5D%7B-x%2B2%7D)
Now we will insert values of x in that definition o h(x) and see if the values we obtain match the corresponding y values in the table:
![h(-6) = \sqrt[3]{-(-6)+2}= \sqrt[3]{6+2}= \sqrt[3]{8} = 2\\h(1) = \sqrt[3]{-1+2}= \sqrt[3]{1}= 1\\h(2) = \sqrt[3]{-2+2}= \sqrt[3]{0}= 0\\h(3) = \sqrt[3]{-3+2}= \sqrt[3]{1}= 1\\h(10) = \sqrt[3]{-10+2}= \sqrt[3]{-8}= -2](https://tex.z-dn.net/?f=h%28-6%29%20%3D%20%5Csqrt%5B3%5D%7B-%28-6%29%2B2%7D%3D%20%5Csqrt%5B3%5D%7B6%2B2%7D%3D%20%5Csqrt%5B3%5D%7B8%7D%20%3D%202%5C%5Ch%281%29%20%3D%20%5Csqrt%5B3%5D%7B-1%2B2%7D%3D%20%5Csqrt%5B3%5D%7B1%7D%3D%201%5C%5Ch%282%29%20%3D%20%5Csqrt%5B3%5D%7B-2%2B2%7D%3D%20%5Csqrt%5B3%5D%7B0%7D%3D%200%5C%5Ch%283%29%20%3D%20%5Csqrt%5B3%5D%7B-3%2B2%7D%3D%20%5Csqrt%5B3%5D%7B1%7D%3D%201%5C%5Ch%2810%29%20%3D%20%5Csqrt%5B3%5D%7B-10%2B2%7D%3D%20%5Csqrt%5B3%5D%7B-8%7D%3D%20-2)
We can see that the values match the table 3, so the table 3 represents points on the graph of h(x)
