2x^2 + 14x = -12
Step 1: Subtract -12 from both sides.
2x^2 + 14x - (-12) = -12 - (-12)
2x^2 + 14x + 12 = 0
Step 2: Factor the left side of the equation.
2(x + 1)(x + 6) = 0
Step 3: Set Factors equal to 0.
x + 1 = 0 or x + 6 = 0
x = -1 or x = -6
Answer:
x = -1 or x = -6
Hope this helps. : )
How to solve your problem
Topics: Algebra, Quadratic Equation
2
+
1
=
−
3
2x+1=x-3
2x+1=x−3
Solve
1
Subtract
1
1
1
from both sides of the equation
2
+
1
=
−
3
2x+1=x-3
2x+1=x−3
2
+
1
−
1
=
−
3
−
1
2x+1{\color{#c92786}{-1}}=x-3{\color{#c92786}{-1}}
2x+1−1=x−3−1
2
Simplify
Subtract the numbers
Subtract the numbers
2
=
−
4
2x=x-4
2x=x−4
3
Subtract
x
x
from both sides of the equation
2
=
−
4
2x=x-4
2x=x−4
2
−
=
−
4
−
2x{\color{#c92786}{-x}}=x-4{\color{#c92786}{-x}}
2x−x=x−4−x
4
Simplify
Combine like terms
Multiply by 1
Combine like terms
=
−
4
x=-4
x=−4
Solution
=
−
4
Answer:
3
Step-by-step explanation:
Given the data: 7 6 5 9 3 4 7 9 5 8
INTERQUARTILE RANGE (IQR) = Q3 - Q1
Rearranging the data: 3, 4, 5, 5, 6, 7, 7, 8, 9, 9
Q3 = 0.75(n+1)th term
Q3 = 0.75(10 + 1) th term
Q3 = 0.75(11)th term = 8.25th term
Taking the 8th term = 8
Q1 = 0.25(11)th term = 2.75th
Taking the average of the 8th and 9th term:
(5 + 5) / 2 = 10/2 = 5
Q3 - Q1 = (8 - 5) = 3
Answer:
-2<x≤5
Step-by-step :
-1<x+1≤6 So fisrt what every we do to one side we must do to the other. In this case it's a bit different since we are dealing with inequalities.
-1<x+1≤6 I would start off by isolating x in the middle.
-1<x+1≤6 I subtracted 1 from all three sides.
-1 -1 -1
Now your equation should look like this:
-2<x≤5 Now there is really nothing much we can do here since we were just trying to get x by its self.
Answer : -2<x≤5
