<h3>The time in fourth race is 43.04 seconds</h3>
<em><u>Solution:</u></em>
Given that,
Shelly is trying to improve her running time for a track race
She ran the first race in 43.13 seconds
Her time was 43.1 seconds in the second race and 43.07 seconds in the third race
<em><u>Therefore, pattern is:</u></em>
43.13, 43.1, 43.07 , ..
<em><u>Find the difference between each terms</u></em>
d = 43.13 - 43.1 = 0.03
d = 43.1 - 43.07 = 0.03
Thus the difference is same
<em><u>If this pattern continues what will shellys time be in the fourth race?</u></em>
Fourth race = third race - 0.03
Fourth race = 43.07 - 0.03 = 43.04
Thus the time in fourth race is 43.04 seconds
40 divided by 33n. hope it helps!
Answer: 3.75z+12
For an equivalent expression, lets simplify the equation.
3/4(5z+16)
multiply both '5z' and '16' by 3/4
3.75z+12
25 students
194 balloons
194/25 = 7.76
Each student gets 7 balloons, 7 x 25 = 175 balloons will be used
194 - 175 = 19 balloons remaining (Answer to part 1 of this question)
If each student needs 8 balloons
8 * 25 = 200
200 - 194 = 6 ballons needed (Answer to part 2 of this question)
We also could have found the answer to part 2 by saying that we had 19 balloons left over when the students each were given 7 balloons
Each student needs another 1 balloon = 25 balloons,
We have 19 left over
25 - 19 = 6 balloons need to be purchased (we got the same answer both ways so it is very likely we have the correct answer)
